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egoroff_w [7]
3 years ago
11

Assume that 140 surveys are completed. Of those surveyed, 71 responded positively to effectiveness, 60 responded positively to s

ide effects, and 65 responded positively to cost. Also, 33 responded positively to both effectiveness and side effects, 31 to effectiveness and cost, 28 to side effects and cost, and 21 to none of the items. How many responded positively to all three?
Mathematics
1 answer:
liraira [26]3 years ago
7 0

Answer:

15

Step-by-step explanation:

Let n(T) denotes total surveys done i.e. n(T)=140

Let n(A) be the no. of responses to positively to effectiveness i.e. n(A)=71

Let n(B) be the no. of side effects i.e.n(B) =60

Let n(C) be the no. of responses to cost i.e. n(C)= 65

33 responded positively to both effectiveness and side effects

So, n(A∩B)=33

31 to effectiveness and cost

n(A∩C)=31

28 to side effects and cost

n(B∩C)=28

21 to none of the items

So, n(A∪B∪C)=140-21 = 119

we are supposed to find ow many responded positively to all three i.e. n(A∩B∩C)

Formula:

n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(A∩C)-n(B∩C)+ n(A∪B∪C)

119=71+60+65-33-31-28+ n(A∪B∪C)

119=104+ n(A∪B∪C)

119-104= n(A∪B∪C)

15= n(A∪B∪C)

Hence 15 responded positively to all three

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Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

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The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

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