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lara [203]
3 years ago
13

What is the principal square root of 64

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
7 0
The answer is 8 because 8x8=64
Alexxx [7]3 years ago
6 0

Answer:

8

Step-by-step explanation:

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A) the only mistake is changing the mixed number to an improper fraction . 
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For the trinomial x2 + 10x + 21, we want to find two binomial factors
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X^2 + 10X + 21

(X + 3)(X + 7)
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3 years ago
How many six digit even numbers can be formed that don't end in 0?
Fudgin [204]
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3rd digit:10
4th digit:10
5th digit:10
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8 0
3 years ago
Of the cars sold during the month of July, 89 had air conditioning, 99 had an automatic transmission, and 74 had power steering.
DedPeter [7]

Answer:

There are a total of 23 cars with air conditioning and automatic transmission but not power steering

Step-by-step explanation:

Let A be the cars that have Air conditioning, B the cars that have Automatic transmission and C the cars that have pwoer Steering. Lets denote |D| the cardinality of a set D.

Remember that for 2 sets E and F, we have that

|E \cup F| = |E| + |F| - |E \cap F|

Also,

|E| = |E ∩F| + |E∩F^c|

We now alredy the following:

|A| = 89

|B| = 99

|C| = 74

|A \cap B \cap C| = 5

|(A \cup B \cup C)^c| = 24

|A \ (B U C)| = 24 (This is A minus B and C, in other words, cars that only have Air conditioning).

|B \ (AUC)| = 65

|C \ (AUB)| = 26

|B \cap C| = 11

We want to know |(A∩B) \ C|. Lets calculate it by taking the information given and deducting more things

For example:

99 = |B| = |B ∩ C| + |B∩C^c| = 11 + |B∩C^c|

Therefore, |B∩C^c| = 99-11 = 88

And |A ∩ B ∩ C^c| = |B∩C^c| - |B∩C^c∩A^c| = |B∩C^c| - |B \ (AUC)| = 88-65 = 23.

This means that the amount of cars that have both transmission and air conditioning but now power steering is 23.

3 0
2 years ago
when derek planted a tree it was 36 inches tall. the tree grew 1 1/4 inches per year the tree is now 44 3/4 inches tall. how man
Vikentia [17]
7 1/2 years ago to be precise

If correct brainley please

Thank you


5 0
3 years ago
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