Answer:
The median height of Sam and his brothers is 135.
Step-by-step explanation:
First, let's find the age of Sam's brothers:
![B_{1} = 140 cm - 5 cm = 135 cm](https://tex.z-dn.net/?f=%20B_%7B1%7D%20%3D%20140%20cm%20-%205%20cm%20%3D%20135%20cm%20)
![B_{2} = 140 cm - 7 cm = 133 cm](https://tex.z-dn.net/?f=%20B_%7B2%7D%20%3D%20140%20cm%20-%207%20cm%20%3D%20133%20cm%20)
The median height of Sam and his brothers is given by the middle number of the three values arranged from lowest to highest:
133 <u>135</u> 140
<em>Since the middle number is 135, then the median height is 135. </em>
Therefore, the median height of Sam and his brothers is 135.
I hope it helps you!
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How do you solve this? [question in attachment]
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In order to find the perimeter of a shape, we should add all of its sides.
Since a triangle has only 3 sides, we add 3 sides together, like so:-
⇒ 9x-7+12x-13+3x+8
Combine like terms:-
➪ 9x+12x+3x-7-13-8
Which simplifies to
➪9x+15x-7-21
On further simplification,
➪24x-28
So we conclude that the perimeter of the triangle is 24x-28 units.
<h3 /><h3>Good luck.</h3>
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Triangles are similar and only differ in size meaning they are dilated
So first we have to find the scale factor of dilation (by how much the smaller triangle got bigger)
Find scale factor:
2.4a=4.8
z=2
Find x:
we multiply the original side of the small side with the scale factor of 2
2.8(2)=x
5.6=x
So, x=5.6
B and e are you best choices hope this helps
let's recall that a year has 12 months, so 15 months is really 15/12 years.
![\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&\$1000\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\to \frac{15}{12}\dotfill &\frac{5}{4} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%7D%20%5C%5C%5C%5C%20I%20%3D%20Prt%5Cqquad%20%5Cbegin%7Bcases%7D%20I%3D%5Ctextit%7Binterest%20earned%7D%5Cdotfill%26%5C%241000%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%246000%5C%5C%20r%3Drate%5Cto%20r%5C%25%5Cto%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B15%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B5%7D%7B4%7D%20%5Cend%7Bcases%7D)
![\bf 1000=(6000)r\left( \cfrac{5}{4} \right)\implies 1000=7500r\implies \cfrac{1000}{7500}=r\implies \cfrac{2}{15}=r \\\\\\ \stackrel{\textit{converting that to a percentage}}{\cfrac{2}{15}\cdot 100 = r\implies \cfrac{40}{3}=r}\implies \stackrel{\%~\hfill }{13.\overline{3}}=r](https://tex.z-dn.net/?f=%5Cbf%201000%3D%286000%29r%5Cleft%28%20%5Ccfrac%7B5%7D%7B4%7D%20%5Cright%29%5Cimplies%201000%3D7500r%5Cimplies%20%5Ccfrac%7B1000%7D%7B7500%7D%3Dr%5Cimplies%20%5Ccfrac%7B2%7D%7B15%7D%3Dr%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bconverting%20that%20to%20a%20percentage%7D%7D%7B%5Ccfrac%7B2%7D%7B15%7D%5Ccdot%20100%20%3D%20r%5Cimplies%20%5Ccfrac%7B40%7D%7B3%7D%3Dr%7D%5Cimplies%20%5Cstackrel%7B%5C%25~%5Chfill%20%7D%7B13.%5Coverline%7B3%7D%7D%3Dr)