So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
Answer:
bro! im in 7th grade i would try to help but im very stupid sorry for the dissopiontment
Step-by-step explanation:
The answer should be 24, because you can mark out 5,and 10 cuz it doesn’t make since
Answer:
Angle A = Angle X
Line Segment CA = Line Segment ZX
Angle Y = Angle B
Line Segment YX = Line Segment BA
Step-by-step explanation:
Both triangles are stated to be equal so we can draw two triangles and label them. One triangle has Point A, Point B, and Point C. The second triangle has Point X, Point Y, and Point Z. Make sure that Point X on the second triangle is in the same spot as Point A on the first triangle (same for points B, C, Y, and Z).
