Hope this helps
<span>2520 = 2^3 x 3^2 x 5 x 7</span>
<u>We'll assume the quadratic equation has real coefficients</u>
Answer:
<em>The other solution is x=1-8</em><em>i</em><em>.</em>
Step-by-step explanation:
<u>The Complex Conjugate Root Theorem</u>
if P(x) is a polynomial in x with <em>real coefficients</em>, and a + bi is a root of P(x) with a and b real numbers, then its complex conjugate a − bi is also a root of P(x).
The question does not specify if the quadratic equation has real coefficients, but we will assume that.
Given x=1+8i is one solution of the equation, the complex conjugate root theorem guarantees that the other solution must be x=1-8i.
Looks fishy to me, the way this problem combines <, = and > symbols.
But anyway. Subtract 3x from both sides. You'll get
5 < x = 2 > 0 2 > 0 is true, but that's a different type of math problem (true or false). If you decide to substitute '1' for 2 > 0, then the "1" says "TRUE."
Then 5 < x = true, so you must find x values that are larger than 5.
That would be (5, infinity)
Please go back and ensure that you have copied down the original problem exactly as it appears.
She would be able to bake 32 muffins hope this helps
