Given the radius of 50 miles and the line joining the cities at (0, 56) and (58, 0), the transmitter signal can be picked during 59.24 miles of the drive.
<h3>How can the duration of signal reception be found?</h3>
Radius of broadcast of the transmitter = 50 miles
Location of starting point = 56 miles north of the transmitter
Location of destination city = 58 miles east of the transmitter
Therefore we have;
Slope of the line joining the two cities
= 56 ÷ (-58) = -0.966
Which gives the equation of the line as follows;
y = -0.966•x + 56
The equation of the circle is;


1.933156•x^2 - 108.192•x + 636 = 0
Which gives;
Therefore;
When x = 6.67, we have;
- y = -0.966 × 6.67 + 56 = 49.56
When x = 49.29, we have;
- y = -0.966 × 49.29 + 56 = 8.4
The length of the drive, during which the driver can pick the signal, <em>l</em>, is therefore;
l = √((49.56-8.4)^2 + (49.29-6.67)^2) = <u>59.24 miles</u>
- The length of the drive during which the signal is received is 59.24 miles
Learn more about the equation of a circle here:
brainly.com/question/502872
#SPJ1
Answer:
(0,2)
Step-by-step explanation:
I'm going to assume you meant Which point is ON the graph of f(x) = 2 * 5^x?
In order to do this question, all you need to do is pick any number as x. Lets pick 0 in this case.
f(x) = 2 * 5^x
f(0) = 2*5^0
= 2*1
= 2
So one point on the graph would be (0,2)
Why?
Because remember with functions, the f(x) can be swapped out with y, so when x = 0, y = 2.
Answer:
2
+ 2
Step-by-step explanation:
= 
= 2
Answer:
.
Step-by-step explanation:
We know that if two corresponding sides of two triangles are equal, then third sides of the triangles depend on angle between equal sides.
Angle opposite to larger side is larger.
Since, 14 < 15, therefore
...(1)
We know that, angle can not not negative.
...(2)
From (1) and (2), we get
Therefore, the range of values of x is
.
Answer:
round answer is : 10 ft
Step-by-step explanation:
The explanation is in the picture!