Let's set it up like this:
Find the LCD, which is 12, and adjust them according to that.
Divide.
Cancel the common factor, which is 12.
That would be our answer!
Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
Answer: No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.
Step-by-step explanation:
Since we have given that
Mean height = 61.5 inches
Standard deviation = 4.4 inches
n = 100
So, test statistic value would be
At 10% level of significance, in two tail test ,
z = 1.28
Since 1.28 > -2.727
So, we will accept the null hypothesis.
Hence, No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.
Answer:
1246 yards
Step-by-step explanation:
To find the yard of fencing she needs for he cows, we simply need to find the perimeter of the rectangular area.
The area is 200 yards by 423 yards.
The perimeter is the sum of all the sides of a rectangle and it is given by:
P = 2(L + B)
P = 2(200 + 423) = 2(623)
P = 1246 yards.
She needs 1246 yards of fencing.
Maybe try dividing 1092 by 21 I got 52
