Tiffany is solving an equation where both sides are quadratic expressions. If the graph of one quadratic opens upward and the ot
her opens downward, what is the greatest possible number of intersections for these graphs?
2 answers:
Answer:
The greatest possible points of intersection of the two graphs could be two.
Step-by-step explanation:
As we are given that:
The graph of one quadratic opens upward and the other opens downward.
We are asked to find the greatest possible point of intersections of the two graph.
Clearly from the graph we could see that the greatest possible points of intersection of two graphs could be 2.
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Answer:
(x + 1)^2 + (y + 2)^2 = 106
Step-by-step explanation:
The formula for a circle is
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) is the center of the circle and r is the raadius
--------------------------------------
The center is the midpoint of the diameter end points
(h, k) = ( (-6 + 4)/2 , (-11 + 7)/2 )
(h, k) = (-1, -2)
The radius is the distance from the center to an endpoint
Using (h, k) and Q
r^2 = (4 - -1)^2 + (7 - -2)^2
r^2 = 5^2 + 9^2
r^2 = 106
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Plug into the circle formula
(x + 1)^2 + (y + 2)^2 = 106
