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valentina_108 [34]
3 years ago
12

Tiffany is solving an equation where both sides are quadratic expressions. If the graph of one quadratic opens upward and the ot

her opens downward, what is the greatest possible number of intersections for these graphs?

Mathematics
2 answers:
lions [1.4K]3 years ago
6 0

Answer:

The greatest possible points of intersection of the two graphs could be two.

Step-by-step explanation:

As we are given that:

The graph of one quadratic opens upward and the other opens downward.

We are asked to find the greatest possible point of intersections of the two graph.

Clearly from the graph we could see that the greatest possible points of intersection of two graphs could be 2.

Alekssandra [29.7K]3 years ago
4 0
<span>greatest </span>possible number of intersections is Two 
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Answer:

The last equation x2 - 2x -4 = 0

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Unless you meant.  -4 and 6  ?

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-------------------------

Or did you mean  x = 1 and x =4 ?...

x^2 + 2x + 4 = 0  :   complete square  x^2 + 2x + 1 + 3 = 0,   (x+1)^2 + 3 = 0

x^2 - 2x + 4 = 0 :  complete square:  (x -1)^2 + 3 = 0

0x^2 + 2x - 4 = 0,    2x - 4 = 0,  x = 2

x^2 - 2x - 4 = 0  becomes:   x^2 - 2x + 1 - 1 -4 = 0 ;  (x - 1)^2 - 5 = 0

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