The answer is 358 but i cant use the number line in this case.
Subtract 52 from m, s, and the total amount of students.. 52 is the amount of students that would take both math and science. m now equals 43, s now equals 23, and the total students remaining is 95.
Since the criteria wants you to exclude students that take math or science, add m and s together.

This is the total amount of students that take math or science.
To find the probability of picking a student that doesn't take math or science, subtract 66 from the total amount of students.

Take this amount and divide by the total amount of students again.

Convert the decimal into a percentage.

%
There is a
30.52% chance of picking a student that doesn't take math nor science.
Yup c the brainliest you say
Answer:
-16p³ + 48p² - 16p
Explanation:
In order to simplify the given expression, we need to multiplied 8p with (-2p²+6p-2)
8p*(-2p²+6p-2)
we need to distribute 8p over the brackets or parenthesis.
=8p*(-2p²) + 8p*(6p) + 8p*(-2)
= 8*(-2)*p*p² + 8*6p*p + 8*(-2)* p
= -16p³ + 48p² - 16p
We can't simplify it more, so that's the final answer.
I hope it's help.
13y-2b=15y
2b=2y
2b=2y
2b=2y