Question

If the sum of three consecutive multiples of 7 is 945. Find the smallest among them​

Answer 1

consider first number is = x

formula,

(n / 2)(first number + last number) = sum,

7/2(x+x+6)= 945

2x+6= 945×2/7

2x+6 = 270

2x= 270-6

x=264/2= 132

Answer the smallest number is 132.