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Nata [24]
4 years ago
12

Which best describes the triangele

Mathematics
1 answer:
Tatiana [17]4 years ago
4 0

Answer:

3 sided closed shape

Step-by-step explanation:

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-5x + y = -1x<br> 10x - 2y = 2
sleet_krkn [62]

Answer: Below is the first one

Step-by-step explanation: Second one is right here x=1/5+y/5

6 0
3 years ago
A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection ac
Oksi-84 [34.3K]

Answer:

  • 3. line y=x
  • 4. 10 units to the right and 4 units up

Step-by-step explanation:

In the attached diagram, the green polygon A"B"C" is the reflection of ABC across the line y=x. Then the purple polygon A'B'C' is the translation of A"B"C" 10 units to the right and 4 units up.

_____

You can tell a reflection is involved, because the clockwise order of A, B, C in the original is reversed to counterclockwise in A'B'C'. The left-right horizontal line AC becomes the down-up vertical line A'C', so you know the reflection is across the line y=x, and not the line y=-x.

After the reflection, point A" is located at (2, -6), so moving it to A'(12, -2) entails a translation 10 units right and 4 units up.

7 0
4 years ago
PLEASE HELP me with this!! no explanation needed:)
Yuki888 [10]

Answer:

B.

Step-by-step explanation:

8 0
3 years ago
If you are given the graph of g (x) = log Subscript 2 Baseline x, how could you graph f (x) = log Subscript 2 Baseline x + 5?
olganol [36]
<h3>Answer: Shift the graph of g(x) up 5 units</h3>

Reasoning:

g(x) = \log_2(x)

f(x) = \log_2(x)+5

We see that f(x) = g(x)+5. Whatever the output of g(x) is, we add on 5 to get the output of f(x). The input is x, while the output is y. Adding 5 to the y output is what shifts every point on g(x) up 5 units to move the entire curve up 5 units.

8 0
3 years ago
Read 2 more answers
What is the area of the region bounded by the lines x= 1 and y= 0 and the curve y=xe^x^2?
Mice21 [21]

Answer:

A = 0.859

Step-by-step explanation:

We want to find the area of the region bounded by the lines x = 1 and y = 0 and the curve y = xe^(x²).

At y = 0, let's find x;

0 = xe^(x²)

Solving this leads to no solution because x is infinity. Thus we can say lower bound is x = 0.

So our upper band is x = 1

Thus,lets find the area;

A = ∫xe(x²) dx between 1 and 0

A = (e^(x²))/2 between 1 and 0

A = ((e¹)/2) - (e^(0))/2)

A = 1.359 - 0.5

A = 0.859

3 0
3 years ago
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