$x^2+3x-10\neq0\\\\x^2+5x-2x-10neq0\\\\x(x-5)-2(x+5)\neq0\\\\(x+5)(x-2)\neq0\to x+5\neq0\ \wedge\ x-2\neq0\\\\x\neq-5\ \wedge\ x\neq2\\\\\dfrac{x+5}{x^2+3x-10}=\dfrac{x+5}{(x+5)(x-2)}=\dfrac{1}{x-2}\\\\Answer:\ x=2$

8 0

3 years ago

Read 2 more answers

What is the function rule for (f+g)(x)?

Alenkinab [10]

Bottom one in the picture

3 0

3 years ago

How are dilation different from other types of transformations?

krok68 [10]

While rotations, translations and reflexions do not alter the volume of the matter, dilation does increases the volume.

So the answer would be, dilation increases the volume while other types of transformations do not.

4 0

3 years ago