The ratio is 8:12 when not simplified.
The simplified ratio is 2:3.
Answer:
P(5 ≤ X ≤ 8) = a rectangle with a width of 3 and height of .15 = 3(.15) = .45
P( 4 ≤ X ≤ 5) = a triangle with a base of 1 and a height of (0.15 -0.05) = .10
So....this area = (1/2)(1)(.10) = .05
And another rectangle with a width of 1 and height of .05 = (1) (.05) = .05
So
Adding these areas
P( 4 ≤ X ≤ 8 ) = .45 + .05 + .05 = .55
Step-by-step explanation:
Hoped this helped!
so, we know both the rectangular prism and the cylinder got filled up to a certain height each, the same height say "h" cm.
we know the combined volume of both is 80 cm³, so let's get the volume of each, sum them up to get 80 then.
![\bf \stackrel{\stackrel{\textit{volume of a}}{\textit{rectangular prism}}}{V=Lwh}~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=4\\ w=2\\ \end{cases}~\hspace{2em}\stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%7D%7D%7B%5Ctextit%7Brectangular%20prism%7D%7D%7D%7BV%3DLwh%7D~~%20%5Cbegin%7Bcases%7D%20L%3Dlength%5C%5C%20w%3Dwidth%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20L%3D4%5C%5C%20w%3D2%5C%5C%20%5Cend%7Bcases%7D~%5Chspace%7B2em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D%5Cpi%20r%5E2%20h%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D1%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
Answer:
x^2 + 2x - 15
Step-by-step explanation:
(x-3)(x+5) = x^2 + 2x - 15
hope this helps, pls mark brainliest :D
