Question

I need help with this question badly

Answer 1

Step-by-step explanation:

${9}^{ - 53} . {9}^{37}$

To solve this question we use the rules of indices

Since the bases are the same and are multiplying we add the exponents using the formula

${a}^{b} \times {a}^{c} = {a}^{b + c}$

So for the above question we have

${9}^{ - 53} \times {9}^{37} = {9}^{ - 53 + 37}$

We have the final answer as

${9}^{ - 16}$

Which is the same as

$\frac{1}{ {9}^{16} }$

Hope this helps you