Solving Systems of Equations by Substitution y=1/2x+5 y=-3/2x-7
1 answer:
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216 raised to the power 1/3 can also be written as cube root of 216.
Changing the given expression to radical form, we can write:
![(216)^{ \frac{1}{3} } \\ \\ = \sqrt[3]{216}](https://tex.z-dn.net/?f=%28216%29%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B3%5D%7B216%7D%20)
216 is the cube of 6 i.e. multiply 6 three times (6 x 6 x 6), you will get 216.
So we can write the above expression as:
![\sqrt[3]{(6)^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%286%29%5E%7B3%7D%20%7D%20)
The cube root and cube cancel out each other, leaving the answer equal to 6.
So, the correct answer is option B
Changing the given expression to radical form, we can write:
216 is the cube of 6 i.e. multiply 6 three times (6 x 6 x 6), you will get 216.
So we can write the above expression as:
The cube root and cube cancel out each other, leaving the answer equal to 6.
So, the correct answer is option B
The area of a rectangle is length + length + width + width, or 2l + 2w. Set these equal.
=
+
+ width + width
= 7 + 2w; subtract 7 from both sides
= 2w; divide both sides by 2
= w, or the width (in meters)
The equation of the parabola that similar to f(x) = but the vertex is (3, 5) in the standard form is y =
+ 5
The equation of the parabola
f(x) =
The standard vertex form of a parabola is
y = + k
The coordinates of the vertex of a parabola = (3, 5)
Where (h, k) is the coordinates
From the given function of the parabola f(x) =
The value of a = 7
Substitute the values in the vertex form of a parabola
y = + 5
Hence, the equation of the parabola that is similar to f(x) = but the vertex is (3, 5) in the standard form is y =
+ 5
Learn more about parabola here
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