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klasskru [66]
3 years ago
6

The scale factor for two similar rectangles is 4. If the area of the smaller rectangle 7m^2, what is the area of the larger rect

angle?
A. 112m ^ 2
B. 28m ^2
C. 196m ^2
D. 121, ^ 2
Mathematics
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

A. 112 m^2

Step-by-step explanation:

If the scale factor is 4, the area of the larger figure is 4^2 times that of the smaller one.

... (7 m^2)·4^2 = 112 m^2

_____

The scale factor for area is the square of the scale factor for linear dimensions. When we talk about a scale factor without qualification, we mean the scale factor for linear dimensions.

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7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)<br>by logarithm laws<br>​
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Answer:

1.5871

Step-by-step explanation:

According to the Question,

  • we have, 7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)

The Solution, With Basic Properties of Log.

7*log15-7*log16+6*log8-6*log3+5*log2-5*log3+log32-log25

7*1.176-7*1.204+6*0.903-6*0.477+5*0.3010-5*0.477+1.505-1.3979

on Solving, We get

1.5871

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What is the side length, in inches, of the pets
tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is 4x-5 inches

Step-by-step explanation:

Given

Area of the square of design = 16x^{2} -40x+25

First we find the roots of equation 16x^{2} -40x+25=0

The roots of the quadratic equation ax^{2} +bx^{2} +c=0 are given by

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a=16, b=-40, c=25

x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}

x=\frac{40\pm\sqrt{1600-1600}}{32}

x=\frac{40\pm\sqrt{0}}{32}

x=\frac{40}{32}

x=\frac{5}{4}

4x=5\\4x-5=0

That is, the factors of the polynomial 16x^{2} -40x+25 are 4x-5 and 4x-5.

So, Area of the square design = 16x^{2} -40x+25 = (4x-5)^{2}

Area of a square = Length^2

Thus, the length of the sign is 4x-5 inches

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