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klasskru [66]
2 years ago
6

The scale factor for two similar rectangles is 4. If the area of the smaller rectangle 7m^2, what is the area of the larger rect

angle?
A. 112m ^ 2
B. 28m ^2
C. 196m ^2
D. 121, ^ 2
Mathematics
1 answer:
nydimaria [60]2 years ago
3 0

Answer:

A. 112 m^2

Step-by-step explanation:

If the scale factor is 4, the area of the larger figure is 4^2 times that of the smaller one.

... (7 m^2)·4^2 = 112 m^2

_____

The scale factor for area is the square of the scale factor for linear dimensions. When we talk about a scale factor without qualification, we mean the scale factor for linear dimensions.

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The circumference of Circle K is $\pi$ . The circumference of Circle L is $4\pi$ . Two circles, one labeled "Circle K" and the o
timurjin [86]

Answer:

Step-by-step explanation:

Given the circumference of Circle K = π

circumference of Circle L = 4π

Ratio of their circumferences = Ck/Cl

Ratio of their circumferences = π/4π

Ratio of their circumferences = 1/4 = 1:4

For their radii

C = 2πr

for circle k with circumference π

π = 2πrk

1 = 2rk

rk = 1/2

for circle l with circumference 4π

4π = 2πr

4 = 2r

r = 4/2

rl = 2

ratio

rk/rl = 1/2/2

rk/rl = 1/4 = 1:4

for the areas

Area of a circle = πr²

for circle k

Ak = π(1/2)²

Ak = π(1/4)

Ak = π/4

for circle l

Al = π(2)²

Al = 4π

Ratio of their areas

Ak/Al = π/4/(4π)

Ak/Al = π/16π

Ak/Al = 1/16 = 1:16

3 0
2 years ago
Write 8.87 as a mixed number and as an improper fraction.<br> Do not try to simplify your answers.
kodGreya [7K]

Answer:

  8 87/100 = 887/100

Step-by-step explanation:

"Eight and eighty-seven hundredths" is ...

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Answer:

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4 0
3 years ago
Which is more, 1 quart or 7 cups?<br><br> A. 1 quart<br> B. 7 cups<br> C. neither; they are equal
cricket20 [7]
1 quart is equal to 4 cups so the answer is B.
5 0
3 years ago
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After traveling exactly half of its journey from station A to station B, a train was held up for 10 minutes. In order to arrive
Alex17521 [72]
Let's define variables:
 s = original speed
 s + 12 = faster speed
 The time for the half of the route is:
 60 / s
 The time for the second half of the route is:
 60 / (s + 12)
 The equation for the time of the trip is:
 60 / s + 60 / (s + 12) + 1/6 = 120 / s
 Where,
 1/6: held up for 10 minutes (in hours).
 Rewriting the equation we have:
 6s (60) + s (s + 12) = 60 * 6 (s + 12)
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 We take the positive root so that the problem makes physical sense.
 s = 60 Km / h
 Answer:
 
The original speed of the train before it was held up is:
 
s = 60 Km / h
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3 years ago
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