Question

9^x+1 - 13(3^x)+4=0​

Answer 1

Answer:

answer 1/6

Step-by-step explanation:

9∧x+1-13(3∧x)+4=0

9∧x-39∧x=-5

-30∧x=-5   (Introduce log base 10 in both sides)

-xlog30=-log5

x=-log5/-log30

x=1/6

Answer 2

Answer: x = -1/8

Step-by-step explanation:

Given the equation 9^x+1 - 13(3^x)+4=0​

First, open the bracket, multiply 13 by 3

9^x+1 - 39^x+4=0​

Combine like terms

9^x - 39^x +4 +1=0​

40^x+5=0

Make x the subject

​40^x=0 -5

40^x= -5

Divide both sides by 40

40^x/40=-5/40

x = -1/8

I hope this is clear, please mark as brainliest answer.