Question

What is the equation in point-slope form of the line that passes through (-9, 12) with a slope of 5/6?​

Answer 1

Answer:

$\large\boxed{y-12=\dfrac{5}{6}(x+9)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

We have

$m=\dfrac{5}{6},\ (-9,\ 12)\to x_1=-9,\ y_1=12$

Substitute:

$y-12=\dfrac{5}{6}(x-(-9))\\\\y-12=\dfrac{5}{6}(x+9)$