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3 years ago

(7-15-3+5-7)×1 step by step

Mathematics

2 answers:

Tresset [83]3 years ago

6 0

Answer:

-13

Step-by-step explanation:

(7−15−3+5−7)⋅1

Subtract 15 from 7 to get −8.

(−8−3+5−7)×1

Subtract 3 from −8 to get −11.

(−11+5−7)×1

Add −11 and 5 to get −6.

(−6−7)×1

Subtract 7 from −6 to get −13.

−13

sertanlavr [38]3 years ago

5 0

Answer:

the answer to this equation is 3

Step-by-step explanation:

have a great day

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If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn

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Let $a=\tan A$ and $b=\sin A$ . Then

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and

$mn=(a+b)(a-b)=a^2-b^2$

$\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}$

The expression under the square root can be rewritten as

$\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)$

Recall that

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Sketch the graph by hand using asymptotes and intercepts, but not derivatives. Then use your sketch as a guide to producing grap

Arisa [49]

The local minima of $f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}$ are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)

<h3>How to determine the local minima?</h3>

The function is given as:

$f\left(x\right)=\ \frac{\left(2x+3\right)^2\left(x\ -2\right)^5}{x^3\left(x-5\right)^2}$

See attachment for the graph of the function f(x)

From the attached graph, we have the following minima:

Minimum = (-1.5, 0)

Minimum = (7.980, 609.174)

The above means that, the local minima are

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(7-15-3+5-7)×1 step by step​

(7-15-3+5-7)×1 step by step