The problem is modelled as right angle triangle, shown in the diagram below
The distance between the pilot and the house is labelled as

Using the trigonometry ratio of sine


Answer:
3(x-4)
Step-by-step explanation:
3×4=12 and 3 also goes into 3x
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jonny [76]
Answer:
side
Step-by-step explanation:
if your talking about the dark purple it would be the side but if your talking about the other one it would be front i cant rlly tell by the colors.
i hope this helps:)
Answer:
T₂ = 421.4 K
Step-by-step explanation:
The temperature, T, of a given mass of gas varies inversely with its Volume,V.

We have,
V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K
V₂ = 70 cm₃
We need to find the new temperature of the gas. Using the above relation to find T₂.

Hence, the required temperature of the gas is 421.4 K.