1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
garik1379 [7]
3 years ago
10

Which rules should be remembered when creating formulas using nested functions? Check all that apply.

Computers and Technology
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

Use an equal sign at the beginning of the formula (A)

Use open and close parenthesis for each set of nested functions (B)

Functions should be in CAPS (E)

Separate functions with commas (F)

Explanation:

Got it right on edj :)

kenny6666 [7]3 years ago
4 0

Answer:

Use an equal sign at the beginning of the formula.

Explanation:

is the ansswer

You might be interested in
If you want to prioritize downloads of your mobile app instead of visits to your mobile site, you should: a) add a sitelink exte
scoray [572]

Answer:

create a Universal App campaign

3 0
3 years ago
Which fonts do not have a practical use in writing
kondaur [170]
To be honest with you, I don’t know but you can always look up on google “which fonts do not have a practical use in writing” and then there are links you can look up for the answer . Sorry but I don’t know which link is the best answer for your question ;) have a great day bro
8 0
3 years ago
The birthday problem is as follows: given a group of n people in a room, what is the probability that two or more of them have t
Julli [10]

Answer:

import random

def calc_birthday_probability(num_people):

   num_tries = 1e6

   num_duplicates = 0

   tries = 0

   while tries < num_tries:

       total_birthday = {}

       for i in range(1, 366):

           total_birthday[i] = 0

       for count in range(num_people):

           birthday = random.randint(1, 365)

           if total_birthday[birthday] != 0:

               num_duplicates += 1

               break

           total_birthday[birthday] += 1

       tries += 1

   return num_duplicates/num_tries

def main():

   num_people = 10

   p = calc_birthday_probability (num_people)

   print(p)

   num_people = 20

   p = calc_birthday_probability (num_people)

   print(p)

   return

if __name__ == "__main__":

   random.seed(2020)

   main()

Explanation:

  • Run the loop until the value of tries is less than num_tries to do number of trials.
  • Run the loop to create the desired number of birthdays by generating random numbers.
  • Increase  the num_duplicates  variable by 1, if the birthday has  already occurred.
  • Lastly define and then call the main function.

4 0
4 years ago
Print Job Cost Calculator (10 points)
Ad libitum [116K]

Answer: Provided in the explanation section

Explanation:

Provided is the code  to run this program

Source Code:

import java.util.Scanner;

class PrintJobCost

{

  public static void main(String[] args) {

      Scanner input=new Scanner(System.in);

      System.out.print("Enter print job info:");

      String info=input.nextLine();

      String size="",type="";

      int count=0,i=0,len=info.length();

      double cost=0.0;

      while(info.charAt(i)!=' '){

          size=size+info.charAt(i);  

          i++;

      }

      i++;

      while(info.charAt(i)!=' '){

          type=type+info.charAt(i);

          i++;

      }

      i++;

      while(i<len){

          count=count*10+Integer.parseInt(String.valueOf(info.charAt(i)));

          i++;

      }

      if(size.equals("Letter"))

          cost=cost+0.05;

      else if(size.equals("Legal"))

          cost=cost+0.06;

      else if(size.equals("A4"))

          cost=cost+0.055;

      else if(size.equals("A5"))

          cost=cost+0.04;

      if(type.equals("Grayscale"))

          cost=cost+0.01;

      else if(type.equals("Colored"))

          cost=cost+0.10;

      cost=cost*count;

      System.out.printf("print job Cost:$ %.2f\n",cost);

  }

}

cheers i hope this helped !!!

8 0
4 years ago
There is a concern to be had about the quality of information found on the internet.
Vlad1618 [11]
Yes there is because there are people who willingly put false, and potentially dagnerous information on the internet to make money. In recent events, "Fake news" is very popular on social media sites such as Facebook. These fake news links post shockingly fake headlines such as the death of a celebrity. People peruising their feeds will click on the fake link and either be taken to a different website, or a virus can even be gotten from the link. The people who posted the news can make money off of how many people click on their article.
4 0
4 years ago
Read 2 more answers
Other questions:
  • True or false
    7·1 answer
  • The Start menu on Windows computers changes based on actions performed by their users. True False
    15·2 answers
  • If you are involved in a collision that results in property damage, injury, or death, you must call
    13·1 answer
  • AT&amp;T reacted to the popularity of the cellular phone by adding several cellular models to its line of regular phones. Availa
    8·1 answer
  • To save a file so that it can be opened on most computers, select the ____ option.
    10·2 answers
  • The local city youth league needs a database system to help track children that sign up to play soccer. Data needs to be kept on
    10·2 answers
  • Which statement is NOT true regarding regular expression quantifiers? Group of answer choices They act on the preceding pattern
    11·1 answer
  • How get end portals in mope
    15·1 answer
  • I need help 50 points and brainiest if you answer
    10·2 answers
  • The CUBE extension enables you to get a subtotal for each column listed in the expression, in addition to a grand total for the
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!