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3 years ago

10

As his empire spread throughout the ancient world, Alexander founded roughly how many cities?

1 answer:

Studentka2010 [4]3 years ago

6 0

About 70 Cities in Total.

For his more noteworthy grandness, Alexander established exactly 70 urban areas in the grounds he vanquished and requested them named after himself. Most celebrated, obviously, is Alexandria in Egypt. In India, when his dearest horse kicked the bucket, he requested a city to be constructed named Bucephala.

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You by a t shirt at the fair that costs the owner $12,but your markup is 30%. Tax is 7%. How much money do you owe

Ulleksa [173]

Answer:

The final price of money of t shirt that I own = $ 16.69

Step-by-step explanation:

Given in question as ,

The t shirt cost to the owner = $12

The markup percentage = 30%

So, now the cost price of t shirt = 30% of 12 + 12

= 3.6 + 12 = $15.6

Tax which is added now = 7%

So, new cost of t shirt = 7% of 15.6 + 15.6

= 1.092 + 15.6 =$ 16.69

Hence , the final price of money of t shirt that I own = $ 16.69 Answer

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3 years ago

Let e f (x) = x2 – 2x - 4 What is the average rate of change for the quadratic function from X = -1 tox to x = 42 Enter your ans

sammy [17]

Answer:

The average rate of change of the given function

A(x) = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function f(x) = x² - 2x -4

And given that x = a = -1 and x=b = 4

The average rate of change of the given function

$A(x) = \frac{f(b)-f(a)}{b-a}$

<u><em>Step(ii):-</em></u>

f(x) = x² - 2x -4

f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1

f(4) = 4² -2(4) -4 = 16 -12 = 4

The average rate of change of the given function

$A(x) = \frac{f(b)-f(a)}{b-a}$

$A(x) = \frac{4-(-1)}{4-(-1)} = \frac{5}{5} = 1$

<u><em>final answer:-</em></u>

The average rate of change of the given function

A(x) = 1

5 0

2 years ago

Read 2 more answers

. A triangle has side lengths of 8, 7, and 14. To the nearest tenth of a degree find the measure of the angle opposite the side

4vir4ik [10]

Given:

The measure of three sides of a triangle are 8, 7 and 14.

To find:

The measure of the angle opposite the side of length 8.

Solution:

According to the Law of Cosine:

$\cos A=\dfrac{b^2+c^2-a^2}{2bc}$

Let a=8, b=7 and c=14, then by using Law of Cosine, we get

$\cos A=\dfrac{7^2+14^2-8^2}{2(7)(14)}$

$\cos A=\dfrac{49+196-64}{196}$

$\cos A=\dfrac{181}{196}$

Taking cos inverse on both sides.

$A=\cos^{-1}\dfrac{181}{196}$

$A=22.561328$

$A\approx 22.6$

Therefore, the measure of the angle opposite the side of length 8 is 22.6 degrees.

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2 years ago

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iogann1982 [59]

5/3 each friend gets 3/5 of the trail mix

8 0

3 years ago

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Leto [7]

Answer: do the math

Step-by-step explanation:

I would go to awnsers.com it will give u the best anwser

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2 years ago