It would be the second one if you follow PEMDAS
Using the definition of expected value, it is found that Ayo can be expected to make a profit of £55.8.
The <em>expected value</em> is given by the <u>sum of each outcome multiplied by it's respective probability.</u>
In this problem:
- The player wins $6, that is, Ayo loses £6, if he rolls a 6 and spins a 1, hence the probability is
.
- The player wins $3, that is, Ayo loses £3, if he rolls a 3 on at least one of the spinner or the dice, hence, considering three cases(both and either the spinner of the dice), the probability is

- In the other cases, Ayo wins £1.40, with
probability.
Hence, his expected profit for a single game is:

For 216 games, the expected value is:

Ayo can be expected to make a profit of £55.8.
To learn more about expected value, you can take a look at brainly.com/question/24855677
I think the answer might be B
Answer:
0.44
Step-by-step explanation:
-3x^2 + 2y^2 + 5xy - 2y +5x^2 - 3y^2
Combine like terms
-3x^2 + 5x^2 = 2x^2 2y^2 - 3y^2 = -1y^2
2x^2 - 1y^2 + 5xy - 2y
Now plug in the solutions Note: it is easier if you have all decimals or all fractions (-1/10=-.1
2(0.5)^2 - 1(-0.1)^2 + 5(0.5)(-0.1) - 2(-0.1)
Simplify:
0.5 - 0.01 - 0.25 + 0.2
0.5 + 0.2 - 0.01 - 0.25
0.7 - 0.26
0.44