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2 years ago

differentiate the function and find the slope of the tangent line at the given value of the independent variable k(x)=1/2+x, x=2

Mathematics

1 answer:

aleksandrvk [35]2 years ago

3 0

I didn't know which equation you were asking about, so I solved for both of them. I hope this helps!

Ignore the first guy who answered this question

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Slope:2, y- intercept: 4

Volgvan

Answer:

y = 2x - 4.

With a slope of 2, you multiply 2 by X, and then subtract y-intercept.

3 0

3 years ago

Read 2 more answers

Find the minimum value , round to 2 decimal places plzzzz!!

kati45 [8]

Answer: look at the minimum in the graph

Step-by-step explanation: Minumum as in of the graphed thing and the minimum/maximum of it or the answer to y or x because that’s impossible

6 0

2 years ago

Can anyone please explain? Need some help :)

DedPeter [7]

Answer:

93.5 square units

Step-by-step explanation:

Diameter of the Circle = 12 Units

Therefore:

Radius of the Circle = 12/2 =6 Units

Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.

Area of the Hexagon = 6 X Area of one equilateral triangle

Area of an equilateral triangle of side length s = $\dfrac{\sqrt{3} }{4}s^2$

Side Length, s=6 Units

$\text{Therefore, the area of one equilateral triangle =}\dfrac{\sqrt{3} }{4}\times 6^2\\\\=9\sqrt{3} $ square units$

Area of the Hexagon

$= 6 X 9\sqrt{3} \\=93.5$ square units (to the nearest tenth)$

7 0

3 years ago

If you want to obtain a Class E license before you turn 18, you must______.

krek1111 [17]

Answer:

here is your answer-:

you must

A. be in compliance with school attendance requirements

B. have proof of employment

C. be a U.S. citizen

D. own a motor vehicle

if it helps you pleassseeeeeeeeeee follow me

4 0

3 years ago

A lighthouse is built on an exposed reef, 4.5 miles off-shore. The shoreline is perfectly straight, and a town is located 6 mile

Alisiya [41]

Answer: 3.94 hours

Step-by-step explanation:

From the question, the following parameters are given:

Distance offshore = 4.5 miles

Distance downshore = 6 miles

Speed when running = 3.4 mph

Speed with boat = 1.8 mph

distance of boat rowing = sqrt(4.5^2 + x^2)

Where

Speed = distance/time

Time = distance/speed

Time = distance of boat rowing/1.8

distance of running = 6 - x

Time = (6-x)/3.4

total travel time

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

dt/dx = x/(1.8×sqrt(4.5^2 + x^2) - 1/3.4

d^2t/dx^2 = +ve at any x

x is at its minimum when dt/dx=0

x/(1.8×sqrt(4.5^2 + x^2) = 1/3.4

x = 6/sqrt(253) × 4.5 = 1.697 miles

Substitute x in

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

We obtaine

t = sqrt(4.5^2 + 1.697^2)/1.8 + (6 - 1.69)/3.4

t = 2.672+ 1.266 = 3.94 hours

7 0

2 years ago