1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ierofanga [76]
2 years ago
12

What is the answer to this been struggling need help ASAP -4 (y+1) > 16

Mathematics
1 answer:
bekas [8.4K]2 years ago
4 0

Answer:

y < -5

Step-by-step explanation:

-4(y+1) > 16

y+1 < -4

y < -5

You might be interested in
Isaac invested $1,800 in an account paying an interest rate of 4.7%
bazaltina [42]

Answer:

$3584.86 or 3600 if rounded to the nearest 100 dollars

Step-by-step explanation:

1800(1.047)^15= 3584.86

you can plug this into a calculator

7 0
2 years ago
Read 2 more answers
-11 - 5x = 6(5x + 4)
gavmur [86]

Answer:

x=-1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is -9x+6y=18 in slope intercept form?
Scrat [10]
The answer to this question would be
y
=
1
6
x
+
3
8 0
3 years ago
Read 2 more answers
simplify 5ab+9a-ab-7a and justify each step as associative , distributive, commutative, or additive property.
Vladimir [108]

Answer:

5ab-ab+9a-7a

ab(5-1)+a(9-7)

4ab+2a

a(4b+2)

7 0
3 years ago
Using the given information, give the vertex form equation of each parabola.
Amanda [17]

Answer:

The equation of parabola is given by : (x-4) = \frac{-1}{3}(y+3)^{2}

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:(\frac{47}{12},-3)

The general equation of parabola is given by.

(x-h)^{2} = 4p(y-k), When x-componet of focus and Vertex is same  

(x-h) = 4p(y-k)^{2}, When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

For value of p:

p=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

p=\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}

p=\sqrt{(\frac{1}{12})^{2}}

p=\frac{1}{12} and p=\frac{-1}{12}

Since, Focus is left side of the vertex,

p=\frac{-1}{12} is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p=\frac{-1}{12}

(x-h) = 4p(y-k)^{2}

(x-4) = 4(\frac{-1}{12})(y+3)^{2}

(x-4) = \frac{-1}{3}(y+3)^{2}

8 0
3 years ago
Other questions:
  • Why is 0 not an identity for subtraction? explain
    9·1 answer
  • A sequence is defined recursively by f(1)=16 and f(n)= f(n-1)+2n. Find f(4)
    12·1 answer
  • 46 lbs of apples cost $414. How much would 29 lbs cost?
    13·1 answer
  • Please help me solve this equation i need step by step explaining 3x + 2= x+4(x+2)
    14·2 answers
  • Jennifer Kent receives 24 paychecks each year. Each check is for $863.50 before deductions. What is Jennifer's weekly salary?
    6·1 answer
  • Please help I will give brainlest or whatever!!
    6·1 answer
  • HELP! If the area of a rectangle is 10x^2+3x-4 and the width is 2x-1, what is the side length of the rectangle?
    14·1 answer
  • Algebra 1
    15·1 answer
  • Which statements are true about the locations of points A and B? Select all that apply. O Point A is at (0, -2). Point A is at (
    9·1 answer
  • 2500 principal earning 4%, compounded quarterly, after 4 years.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!