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2 years ago

What is the answer to this been struggling need help ASAP -4 (y+1) > 16

Mathematics

1 answer:

bekas [8.4K]2 years ago

4 0

Answer:

y < -5

Step-by-step explanation:

-4(y+1) > 16

y+1 < -4

y < -5

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Julie went to the store with $20.00. if she bought 8 cans of dog food for $.67 per can, how much money did she have left? IF YOU

Georgia [21]

Answer:

$14.64

Multiply 8 by .67 which is 5.36

Subtract 5.36 from 20.00 and that's 14.64

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3 years ago

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The average score of students in Mr. Blake's science class was 73 with a standard deviation of 11, while the average score of st

Pani-rosa [81]

Answer:

Mr Blake's science class

Step-by-step explanation:

The standard deviation is a measure of variation.

It tells us how far each of the data set in the distribution are far from the mean of the distribution.

The average score of students in Mr. Blake's science class was 73 with a standard deviation of 11, while the average score of students in Mrs. Arnold's class was 75 with a standard deviation of 10.

Since 11>10, Mr Blake's science class is more variable than Mrs. Arnold's class.

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2 years ago

at marshall middle school students choose one main dish one vegtable and one fruit eachday.how many luch combinations are avalil

Setler [38]

Answer:

Step-by-step explanation:

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3 years ago

Evaluate the expression when p = 4. p^2+5 no links pls

inna [77]

Answer:

Step-by-step explanation:

when p is 4

p² + 5 = 4² + 5

16 + 5 = 21

7 0

2 years ago

Mathematics 13 don’t understand

UNO [17]

Answer:

1/6^3

Step-by-step explanation:

The applicable rules of exponents are ...

a^-b = 1/a^b

(a^b)(a^c) = a^(b+c)

Your expression can be simplified as follows:

$\dfrac{6^{-5}}{6^{-2}}=\dfrac{1}{(6^{-2})(6^5)}=\dfrac{1}{6^{-2+5}}=\boxed{\dfrac{1}{6^3}}$

_____

<em>Additional comment</em>

If you think of an exponent as signifying repeated multiplication, the rules of exponents may be easier to remember. The exponent tells you how many times the base is a factor in the product.

Consider multiplication:

$(x\cdot x\cdot x)\cdot(x\cdot x)=x^3\cdot x^2=x^{3+2}=x^5\\\\(x\cdot x\cdot x)\cdot(x\cdot x\cdot x)=(x^3)^2=x^{3\cdot2}=x^6$

Consider division:

$\dfrac{x\cdot x\cdot x}{x\cdot x}=x\quad\Longleftrightarrow\quad\dfrac{x^3}{x^2}=x^{3-2}=x^1\\\\\dfrac{x\cdot x}{x\cdot x\cdot x}=\dfrac{1}{x}\quad\Longleftrightarrow\quad\dfrac{x^2}{x^3}=x^{2-3}=x^{-1}$

This may help you see that a positive exponent in the denominator is equivalent to a negative exponent in the numerator (and vice versa).

6 0

2 years ago