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Norma-Jean [14]
3 years ago
5

Is -(12/-17) equal to 12/17

Mathematics
1 answer:
maria [59]3 years ago
3 0
Yes <span>-(12/-17) is equal to 12/17

I hope this helps. 

Have a awesome day. :)</span>
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Find the amount of time.<br> I = $60, P= $400, r = 5%<br> Find how many years
Keith_Richards [23]

I=PRT

$60= 400 ×.05 × t

$60= 20× t

t= 60/20

3=t

4 0
3 years ago
Rewrite with only sin x and cos x.
Annette [7]

Option A

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

cos 3x = cos(x + 2x)

We know that,

\cos (a+b)=\cos a \cos b-\sin a \sin b

Therefore,

\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x  ---- eqn 1

We know that,

\sin 2 x=2 \sin x \cos x

\cos 2 x=\cos ^{2} x-\sin ^{2} x

Substituting these values in eqn 1

\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)  -------- eqn 2

We know that,

\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x

Applying this in above eqn 2, we get

\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)

\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}

\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x

Therefore,

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

Option A is correct

7 0
3 years ago
EASY QUESTION AND I WILL GET U BRAINLIEST! Xd PLEASE HELPPPP
QveST [7]

Answer:

Box plots

Step-by-step explanation:

Box plots only show the bounds of data results - you can't count the number of inputs/observations.

8 0
3 years ago
Read 2 more answers
What are the solutions to the equation <br><img src="https://tex.z-dn.net/?f=%20%7Cx%20-%208%7C%20%20%2B%202%20%3D%2020" id="Tex
nexus9112 [7]

Answer:

Solutions are -10 and 26

Step-by-step explanation:

( - the abolute sign I'm using

( x - 8 ) + 2 = 20

( x - 8 ) = 18

x - 8 = 18 (postive case)

x - 8 + 8 = 18 + 8

x = 26

( x - 8 ) = 18

x - 8 = -18 (negative case)

x - 8 + 8 = -18 + 8

x = -10

8 0
3 years ago
Multiplying fracions with different numerators
Serjik [45]
So, this means that you are multiplying both of the numerators and denominators together to get the product
6 0
3 years ago
Read 2 more answers
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