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Paul [167]
2 years ago
5

To the nearest tenth, which is the perimeter of ABC. Geometry

Mathematics
2 answers:
qwelly [4]2 years ago
3 0

Answer:

23.6

Step-by-step explanation:

<u><em>Finding AC:</em></u>

Cos 61 = \frac{adjacent}{hypotenuse}

0.48 × 10 = Adjacent

AC = 4.8

<u><em>Now, CB:</em></u>

Cos 29 = \frac{adjacent}{hypotenuse}

0.87 × 10 = CB

CB = 8.8

<u><em>The perimeter:</em></u>

=> 10+4.8+8.8

=> 23.6

devlian [24]2 years ago
3 0

Answer:

23.6

Step-by-step explanation:

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