Question

Radium-226, a common isotope of radium, has a half-life of 1,620 years. how many grams of a 120-gram sample will remain after t years? which equation can you use to solve this problem?

Answer 1

Answer:

$y=120*(\frac{1}{2})^{\frac{t}{1620}}$

Step-by-step explanation:

We have been given that Radium-226, a common isotope of radium, has a half-life of 1,620 years.

We will use half life formula to solve our given problem.  

$y=a*(\frac{1}{2})^{\frac{t}{h}}$, where,  

$a=\text{Initial value}$,

$t=\text{Time}$,

$h=\text{Half life}$.

As we are told that the sample has 120 grams, this means that a equals 120. Upon substituting our given values in half life formula we will get,

$y=120*(\frac{1}{2})^{\frac{t}{1620}}$

Therefore, the equation $y=120*(\frac{1}{2})^{\frac{t}{1620}}$ represents the remaining amount of Radium-226 after t years.

Answer 2

Answer: edge

p(T)=120(1/2)^t/1620

Step-by-step explanation: