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svp [43]
3 years ago
12

A cup contains seven red erasers, four

Mathematics
1 answer:
Wewaii [24]3 years ago
5 0

Answer:

17/50

Plzzzz give me Brainliest!  

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How do you graph y=8.5x
vladimir1956 [14]

Answer:

You graph in the middle of the box

Step-by-step explanation:

go up 8 and to the right of box half way in the middle

8 0
2 years ago
6.8 Use the Normal approximation. Suppose we toss a fair coin 100 times. Use the Normal approximation to find the probability th
Maru [420]

Answer:

(a) The probability that proportion of heads is between 0.30 and 0.70 is 1.

(b) The probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

Step-by-step explanation:

Let <em>X</em> = number of heads.

The probability that a head occurs in a toss of a coin is, <em>p</em> = 0.50.

The coin was tossed <em>n</em> = 100 times.

A random toss's result is independent of the other tosses.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 100 and <em>p</em> = 0.50.

But the sample selected is too large and the probability of success is 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of \hat p<em> </em>(sample proportion of <em>X</em>) if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=100\times 0.50=50>10\\n(1-p)=100\times (1-0.50)=50>10

Thus, a Normal approximation to binomial can be applied.

So,  \hat p\sim N(p,\ \frac{p(1-p)}{n})

\mu_{p}=p=0.50\\\sigma_{p}=\sqrt{\frac{p(1-p)}{n}}=0.05

(a)

Compute the probability that proportion of heads is between 0.30 and 0.70 as follows:

P(0.30

                              =P(-4

Thus, the probability that proportion of heads is between 0.30 and 0.70 is 1.

(b)

Compute the probability that proportion of heads is between 0.40 and 0.65 as follows:

P(0.40

                              =P(-2

Thus, the probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

6 0
3 years ago
The students in Ms. Shen’s class are making decoupage boxes. Each box has 6 sides that can be covered by images. There are 20 st
mrs_skeptik [129]
3 because 20/6=3.3333333333 so you would have 3 because you can split the pictures
3 0
3 years ago
According to the ASA theorem, which of the following sets of relationships can be used to show that VRT and STR are congruent?
irina [24]

Answer:

C. ∠SRT≅∠VTR and ∠STR≅∠VRT

Step-by-step explanation:

Given:

Quadrilateral is a parallelogram.

RS║VT; RT is an transversal line;

Hence By alternate interior angle property;

∠SRT≅∠VTR

∠STR≅∠VRT

Now in Δ VRT and Δ STR

∠SRT≅∠VTR (from above)

segment RT= Segment RT (common Segment for both triangles)

∠STR≅∠VRT (from above)

Now by ASA theorem;

Δ VRT ≅ Δ STR

Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT

7 0
3 years ago
U(8, 9) and V(2, 5) are the endpoints of a line segment. What is the midpoint M of that line segment?
Crazy boy [7]

Answer:

(5, 7 )

Step-by-step explanation:

Given 2 points (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

here (x₁, y₁ ) = U(8, 9) and (x₂, y₂ ) = V(2, 5), thus

midpoint = [0.5(8 + 2), 0.5(9 + 5) ] = [0.5(10), 0.5(14) ] = (5, 7 )

6 0
3 years ago
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