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V125BC [204]
3 years ago
10

Math help please will give brainliest 10 points!!

Mathematics
1 answer:
mestny [16]3 years ago
3 0
17. Its answer C i wil tell you the other one in a sec
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Help me please i need a 67 becasue i cant play games tommorwo if i get 64
liubo4ka [24]

Step-by-step explanation:

3 ÷ 5 is 0.6

0.6 is the answer

8 0
4 years ago
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Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

x^2-3x=x(x-3)

The x-3 terms cancel, leaving you with

\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}

and the limand is continuous at x=3, so we can substitute it to find the limit has a value of -1/18.

7 0
3 years ago
Charles needs construction paper to finish a project. To wrap the box he knows he needs a lot of construction paper. The box is
san4es73 [151]

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304

Step-by-step explanation:

3 0
3 years ago
Three fewer than one fourth of x is 12
Wittaler [7]
The answer is 1/4 x - 3 = 12
6 0
4 years ago
A man claims to have extrasensory perception (ESP). As a test, a fair coin is flipped 23 times, and the man is asked to predict
77julia77 [94]

The probability that he would have done at least this well if he had no ESP is 0.99979

<h3>What is the probability of determining that he would have done well with no ESP?</h3>

To determine the probability, we need to first find the probability of doing well with ESP.

The probability of having 20 correct answers out of 23 coin flips is:

\mathbf{=(\dfrac{1}{2})^{20}}

Since we have 20 correct answers, we also need to find the probability of getting 3 answers wrong, which is:

\mathbf{=(\dfrac{1}{2})^{3}}

There are (^{23}_{20}) = 1771 ways to get 20 correct answers out of 23.

Therefore, the probability of doing well with ESP is:

\mathbf{= 1771 \times (\dfrac{1}{2})^{20}} \times (\dfrac{1}{2})^{3}}

= 0.00021

The probability that he would have at least done well if he had no ESP is:

= 1 - 0.00021

= 0.99979

Learn more about probability here:

brainly.com/question/24756209

#SPJ1

8 0
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