Answer:
The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?
Step-by-step explanation:
SimplifyingY + -9 = 4(x + -2)
Reorder the terms:-9 + Y = 4(x + -2)
Reorder the terms:-9 + Y = 4(-2 + x)-9 + Y = (-2 * 4 + x * 4)-9 + Y = (-8 + 4x)
Solving-9 + Y = -8 + 4x
Solving for variable 'Y'.
Move all terms containing Y to the left, all other terms to the right.
Add '9' to each side of the equation.-9 + 9 + Y = -8 + 9 + 4x
Combine like terms: -9 + 9 = 00 + Y = -8 + 9 + 4xY = -8 + 9 + 4x
Combine like terms: -8 + 9 = 1Y = 1 + 4x
SimplifyingY = 1 + 4x
Answer:
A. O 5
Step-by-step explanation:
1830 ÷ 31 = 59.032258...
The first non-zero digit of the quotient is 5.
Answer:
Can you maybe elaborate the question with the help of brackets I guess ...?
It is difficult to understand the question this way .
The answer is D they are proportional equal to negative 4<span />