Question

Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of negative 35.84 degrees Upper C and a boiling point of 310.69 degrees Upper C . What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid​ state? (Hint: Upper C equals five ninths left parenthesis Upper F minus 32 right parenthesis ​) Express the range as an inequality. Let x represent the temperature in degrees Fahrenheit. What is the range of temperatures for which this substance is not in a liquid​ state? nothing ​(Type an inequality or a compound inequality. Simplify your answer. Use integers or decimals for any numbers in the expression. Round to three decimal places as​ needed.)

Answer 1

Answer:

96.512 °F < x < 591.242 °F

Step-by-step explanation:

We are given;

Melting point = 35.84 °C

Boiling point = 310.69 °C

Now, we are given that formula to convert °C to °F is;

°C = (5/9)°F

Thus if the temperature in Fahrenheit is x, then;

Melting point is; 35.84 °C = (5/9)x°F - "32"

x = ((9 × 35.84)/5) + 32

x = 96.512 °F

Similarly, for Boiling point;

Boiling point is;

310.69 °C = (5/9)x°F - "32"

x = ((9 × 310.69)/5) + 32

x = 591.242 °F

Now, we are told that matter is in its liquid form when it is between melting and boiling point.

Thus, range of x in inequality form is;

96.512 °F < x < 591.242 °F