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Leya [2.2K]
3 years ago
10

What is the answer

align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Aleks [24]3 years ago
8 0
The answer for the question is -32.
Karo-lina-s [1.5K]3 years ago
4 0
Your answer is -32......
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Abc is equilateral with AB=3x-2,BC=2x+4, and CA= x+10
yan [13]
AB = BC, so 3x-2 = 2x+4.  Also, BC = CA, so 2x+4=x+10.

Solve this system of linear equations:

3x-2 = 2x+4
2x+4=x+10 => x=6

Check:  Does AB=BC?  Does AB=BC?

Does 3(6)-2 = 2(6)+4?  Does 16=16?  YES.
Does BC = CA?  Does 2(6)+4 = 6+10?  YES

x = 6 (answer)
7 0
4 years ago
75.2515 rounded to the tenth place is 80 <br><br> Is this right??
Burka [1]

Answer: False

The tenth place means there will be 1 decimal.

75.2515

because they 5 is left to the 2, and 5 means we round up, the 2 becomes a 3. Therefore, it would equal 75.3

3 0
3 years ago
Read 2 more answers
Pleas answer correct answer
Minchanka [31]

Step-by-step explanation:

well, what would you think ?

since the line NO bisects the angle at N (MNO), it bisects also the line MO.

"bisecting" simply means "cutting in half". that means both resulting parts are equally large.

therefore, MO = PO = 8

5 0
3 years ago
Find r if 0=pi/6 rad sector 64m^2
kap26 [50]

Given:

Area of a sector = 64 m²

The central angle is \theta=\dfrac{\pi}{6}.

To find:

The radius or the value of r.

Solution:

Area of a sector is:

A=\dfrac{1}{2}r^2\theta

Where, r is the radius of the circle and \theta is the central angle of the sector in radian.

Putting A=64,\theta=\dfrac{\pi}{6}, we get

64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}

64=\dfrac{\pi}{12}r^2

64\times \dfrac{12}{\pi}=r^2

\dfrac{768}{\pi}=r^2

Taking square root on both sides, we get

\sqrt{\dfrac{768}{\pi}}=r

16\sqrt{\dfrac{3}{\pi}}=r

Therefore, the value of r is 16\sqrt{\dfrac{3}{\pi}} m.

6 0
3 years ago
The sum of all proportions in a frequency distribution should be______.
NeX [460]
It should always be 100
8 0
1 year ago
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