All categories

3 years ago

Maleek reads 1/8 of a book each night. How long will it take him to read 3/4 of the book. Explain fully

1 answer:

3 0

The answer is 5 days because....

you need to find a common multiple for the denominator for 1/8 & 3/4. so 2.
and whatever you do to the bottom you do to the top so 1 3X 2 6
- - = -
8 4 X 2 8

So 6/8 to to 1/8 is 5/8 so it will be 5 days

sorry its confusing i hope it helps

You might be interested in

What is the solution of x=2+\sqrt(x-2) x = 2 x = 3 x = 2 or x = 3 no solution

svp [43]

$D:x\geq2\\\\
x=2+\sqrt{x-2}\\
\sqrt{x-2}=x-2\\
x-2=x^2-4x+4\\
x^2-5x+6=0\\
x^2+x-6x+6=0\\
x^2-2x-3x+6=0\\
x(x-2)-3(x-2)=0\\
(x-3)(x-2)=0\\
x=3 \vee x=2$

5 0

3 years ago

Read 2 more answers

you have decided to purchase a car for $15,699. the credit union requires a 10% down payment and will finance the balance with a

ycow [4]

Its D! Hope this helps :))

8 0

2 years ago

Write the equation of circle b with center B(-2,3) that passes through (1,2)

professor190 [17]

Answer:

$(x+2)^2 + (y-3)^2 = 10$

Step-by-step explanation:

The standard equation for circle is

$(x-a)^2 + (y-b)^2 = r^2$

where point (a,b) is coordinate of center of circle and r is the radius.

______________________________________________________

Given

center of circle =((-2,3)

let r be the radius of circle

Plugging in this value of center in standard equation for circle given above we have

$(x-a)^2 + (y-b)^2 = r^2 \ substitute (a,b) \ with (-2,3) \\=>(x-(-2))^2 + (y-3)^2 = r^2 \\=>(x+2)^2 + (y-3)^2 = r^2 (1)$

Given that point (1,2 ) passes through circle. Hence this point will satisfy the above equation of circle.

Plugging in the point (1,2 ) in equation 1 we have

$\\=>(x+2)^2 + (y-3)^2 = r^2 \\=> (1+2)^2 + (2-3)^2 = r^2\\=> 3^2 + (-1)^2 = r^2\\=> 9 + 1 = r^2\\=> 10 = r^2\\=> r^2 = 10\\$

now we have value of r^2 = 10, substituting this in equation 1 we have

Thus complete equation of circle is $=>(x+2)^2 + (y-3)^2 = r^2\\=>(x+2)^2 + (y-3)^2 = 10$

7 0

3 years ago

Find the domain and range of f(x) = 2 square root of x-2

Neporo4naja [7]

$f(x)=2\sqrt{x-2}\\\\The\ domain:\\x-2\geq0\to x\geq2\\\boxed{x\in[2;\ \infty)}\\\\The\ range:\\\boxed{y\in[0;\ \infty)}$

$If\ f(x)=2\sqrt{x}-2,\ then\\\\The\ domain:\boxed{x\in[0;\ \infty)}\\\\The\ range:\boxed{y\in[-2;\ \infty)}$

5 0

3 years ago

12 oz for $1.39 or 14 oz for $1.49

Inessa05 [86]

The shared variance is (coefficient of determination) is .36.

4 0

3 years ago