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3 years ago

-8+4u=-28 Simplify your answer as much as possible

Mathematics

2 answers:

Nuetrik [128]3 years ago

8 0

Step-by-step explanation:

-8+4u=28

Transposing -8 to Rhs. 

4u=-28+8

4u=-20

Dividing both sides by 4

4u÷4=-20÷4

u=-5. 

THANK YOU

yulyashka [42]3 years ago

6 0

The answer would be -5

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Step-by-step explanation:

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4 years ago

Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.

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3 years ago

Help help legit answers only

Ne4ueva [31]

Answer:

x ≈ 46.7°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin x = $\frac{opposite}{hypotenuse}$ = $\frac{OP}{NP}$ = $\frac{4}{5.5}$ , then