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STatiana [176]
3 years ago
6

What are some effective methods for scrolling? Check all that apply.

Computers and Technology
1 answer:
Tju [1.3M]3 years ago
7 0
The first 3 should be the answer
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Which type of hacker represents the highest risk to your computer?
Deffense [45]

Answer:

The hacker which represents the highest risk to my computer is the Script Kiddie.

Explanation:

A Script Kiddie cannot make their own programs.

They hack by using existing codes, scripts, web shells etc to access a work station, mutilate webpages etc.

The difference between a Hacker and a Script Kiddie is that a hacker does not need another person's code. They are skilled at writing their own codes which are can be very potent. This level of skill can be difficult to attain except for very bright minds.

The script kid needs very little knowledge of scripts and they are well on their way to causing damage.

Cheers!

4 0
3 years ago
In a word processing program, under which tab or menu option can you adjust the picture brightness?
Otrada [13]
B. format because changing the brightness of the photo is changing its default format
5 0
3 years ago
Read 2 more answers
Transition words and phrase in a paragraph
balandron [24]

Answer:

Msms

Explanation:

8 0
3 years ago
Read 2 more answers
In a spreadsheet, equations that use addition, subtraction, multiplication, and division operators, as well as values and cell r
timama [110]

The equations that uses addition, subtraction, multiplication and division operators and other values in a spread sheet is known as formulas. They are a way of having to provide symbols in means of expressing information regarding a mathematical formula that are being solved or showing its solution along with it.

4 0
3 years ago
Mix ‘em Let s1 and s2 be 2 c-strings of the same length. Write a function char* mixem(char*s1, char* s2) which returns a c-strin
Shkiper50 [21]

Answer:

See Explaination

Explanation:

#include <iostream>

#include <string.h>

using namespace std;

char *mixem(char *s1, char *s2);

int main() {

cout << mixem("abc", "123") << endl;

cout << mixem("def", "456") << endl;

return 0;

}

char *mixem(char *s1, char *s2) {

char *result = new char[1 + strlen(s1) + strlen(s2)];

char *p1 = s1;

char *p2 = s2;

char *p = result;

while (*p1 || *p2) {

if (*p1) {

*p = *p1;

p1++;

p++;

}

if (*p2) {

*p = *p2;

p2++;

p++;

}

}

*p = '\0';

return result;

}

5 0
3 years ago
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