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Elanso [62]
3 years ago
14

Sarah is training to run a race. She runs 1 mile per day for the first week. She doubles that and runs 2 miles each day for the

second week. She doubled her daily run again for the third week. How many miles did she run if she ran everyday those three week? Challenge question...
Mathematics
1 answer:
swat323 years ago
8 0

Answer:

She would have ran 48 miles, (if i did my math correctly)

Step-by-step explanation:

7 x 1 = 7

7 x 2 = 13

7 x 4 = 28

7+13+28 =48

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There are a total of 15 dimes and quarters in a covered cup. The value of all 15 coins totals 2.85
QveST [7]

Answer:

There are 6 dimes and 9 quarters.

Step-by-step explanation:

Represent the number of dimes and the number of quarters by d and q.

Then d + q = 15, or q = 15 - d.

Also, ($0.25)q + ($0.10)d = $2.85, or 5q + 2d = 57.

Substituding 15 - d for q, we get 5(15 - d) + 2d = 57, or

75 - 5d + 2d = 57, or

75 - 3d = 57, or

3d = 18.  Thus, there are 6 dimes.  Since q = 15 - d, q = 15 - 6 = 9.

There are 6 dimes and 9 quarters.

6 0
3 years ago
Jason paints 1/4 of the area of his living room walls,w,on Monday. On Tuesday, he paints twice as much as he painted on Monday.
zepelin [54]
1 - (1/4 + 2*1/4)
1 - 3/4
1/4 of the living room still remains unpainted.
8 0
3 years ago
Read 2 more answers
What is the oblique asymptote of the function f(x) x^2+x-2/x+1
Mamont248 [21]
f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}


\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
=0

Consequently, t<span>he limit of f(x) as x approaches infinity is x.

In other words, f(x) approaches the line y=x, 
</span><span>
so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.</span>

3 0
3 years ago
Can u help me with my work don’t send a link !!!
lisov135 [29]

Answer:

A and C

Step-by-step explanation:

ez math

6 0
3 years ago
Read 2 more answers
A 20-person fraternity is making their weekend plans around 5 different parties in IV. Each brother will attend exactly one of t
skad [1K]

Answer:

3876

Step-by-step explanation:

Given the following :

Fraternity members = 20

They are to attend 5 different parties in groups of 4

Meaning a group = 4 persons

Atleast one brother will attend exactly one of the parties. (the brothers are indistinguishable).

Then, exactly one brother at a party (20 - 1) = 19, since they are indistinguishable.

Group members are in 4's

19C4

From: nCr = n! /(n-r)! r!

19C4 = 19! / (19 - 4)! 4!

= 19! / 15! 4!

= (19 * 18 * 17 * 16) / (4 * 3 * 2)

= 93024 / 24

= 3876

3 0
3 years ago
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