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Nutka1998 [239]
3 years ago
5

Ignore the top just answer both of the questions at the bottom plz

Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0

Answer:

y = 5x+2   ,    y=x-6

Step-by-step explanation:

just by looking at the table you can see for the first one 5x + 2 satisfies the table, and x-6 satisfies the right table.

dlinn [17]3 years ago
4 0

for the first table the equation is:

x(5) + 2 = y

and for the second it's:

x - 6 = y

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Warren owes $1,000 for a new laptop. He pays $100 each week.
lana [24]

Answer:

b) In 10 weeks, the loan is paid in full.

Step-by-step explanation:

10×$100=$1000

7 0
2 years ago
Read 2 more answers
(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

3 0
3 years ago
Help ASAP with this question
Serjik [45]
I would say either a or b

3 0
3 years ago
Divide (5x + 6x^3 - 8) ÷(x - 2) PLEASE HELP DUE IN 5 MINUTES ​
Leya [2.2K]

Answer:

6x^2+12x+29+50/x-2

Step-by-step explanation:

3 0
2 years ago
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h
Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

P(t) = P(0)(1+r)^{t}

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that r = 0.047

$172000 in 2004

This means that P(0) = 172000

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

P(t) = P(0)(1+r)^{t}

249000 = 172000(1.047)^{t}

(1.047)^{t} = \frac{249000}{172000}

\log{(1.047)^{t}} = \log{\frac{249000}{172000}}

t\log(1.047) = \log{\frac{249000}{172000}}

t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}

t = 8.05

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

8 0
3 years ago
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