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3 years ago

The sum of two consecutive numbers is -49 what are they

Mathematics

2 answers:

Sholpan [36]3 years ago

7 0

Answer:

-24 and -25

Step-by-step explanation:

-24 and -25

because (-24) + (-25) = -49

Levart [38]3 years ago

5 0

Answer:

22(24)(26) = 13728.

Step-by-step explanation:

Because the next two numbers are consecutive even integers, we can call represent them as x + 2 and x + 4. We are told the sum of x, x+2, and x+4 is equal to 72. This means that the integers are 22, 24, and 26. The question asks us for the product of these numbers, which is 22(24)(26) = 13728.

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Oceanside bike rental shop charges fourteen dollars plus nine dollars an hour for renting a bike . Jason paid fifty-nine dollars

Dafna11 [192]

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2 years ago

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Daniel [21]

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2 years ago

Write the slope-intercept form of the equation that passes through the point (4,-6) and is parallel to the line y = -3/4x - 5

Karolina [17]

The equation that runs through the location (4,-6) has the slope-intercept form, $y=-\frac{3}{4}x-3$ .

<h2>Formation of the equation</h2>

A line's equation written in the slope-intercept form:

y=mx+b

where m= slope & b= y-intercept

The slope of two parallel lines is equal.

Currently, we know the line's equation:

$y=-\frac{3}{4} x-5$

here, slope, m= $-\frac{3}{4}$

A line equation is created by adding the slope's value and the point's coordinates (4, -6):

$-6=-\frac{3}{4}(4)+b$

⇒ -6=-3 +b [adding 3 to both sides]

⇒-3=b

⇒b= -3

Hence the solution is $y=-\frac{3}{4}x-3$ .

Learn more about slope-intercept form here:

brainly.com/question/9682526

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5 0

1 year ago

Sec(x)-tan(x)=1/sec(x)+tan(x)

Rama09 [41]

Answer:

Step-by-step explanation:

I assume that you mean

sec(x)-tan(x) = 1 / ( sec(x) + tan(x) ) , right ?

then this is equivalent to

[ sec(x) - tan(x) ] x [ sec(x) + tan(x) ] = 1

let s evaluate it, we got

sec2(x) - sec(x)tan(x) + - sec(x)tan(x) - tan2(x) = sec2(x) - tan2(x)

= (1 - sin2(x) ) / cos2(x) = cos2(x) / cos2(x) = 1

as cos2(x) + sin2(x) = 1

3 0

2 years ago

Help with num 9 please. thanks

Alik [6]

Answer:

See Below.

Step-by-step explanation:

We want to show that the function:

$f(x) = e^x - e^{-x}$

Increases for all values of <em>x</em>.

A function is increasing whenever its derivative is positive.

So, find the derivative of our function:

$\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]$

Differentiate:

$\displaystyle f'(x) = e^x - (-e^{-x})$

Simplify:

$f'(x) = e^x+e^{-x}$

Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of <em>x.</em>

8 0

3 years ago