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3 years ago

9

Complete the following equivalent ratios by filling in the blank squares:

1 answer:

Alexxandr [17]3 years ago

4 0

Answer:

2:3 = 4:6

4:1 = 24:6

Step-by-step explanation:

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PLEASE ANSWER I NEED HELP!!..

nikitadnepr [17]

Please don't post masses of questions all at once. 1-2 problems per post would be more realistic and fairer to others who need help.

Regarding <span>x-2/5 = 1/5

We are to solve for x. To do this, let's remove the fractions by mult. all 3 terms by 5. Then 5x - 2 = 1, or 5x = 3.

Dividing both sides by x, we get x = 3/5 (answer). Check this by subst. 3/5 into the original equation.</span>

5 0

3 years ago

Fill in the blank.<br> (5x)2<br> a0x2

Yuki888 [10]

Answer: $a_0=25$

Step-by-step explanation:

It is given that, $(5x)^2=a_0x^2$

We need to find the value of $a_0$

As $(5x)^2=a_0x^2$

Solving LHS

$25x^2=a_0x^2$

Now comparing the coefficients of $x^2$

In LHS the coefficient of $x^2$ is 25

In RHS the coefficient of $x^2$ is $a_0$

It implies that, $a_0=25$

So, the value of $a_0$ is 25.

5 0

3 years ago

PLEASE HELP TOP ANSWER GETS BRAINLIEST!! ***Solve for m: 3.2(4m + 10) – (-7.2m) = 37 ***!!!!!!!

alisha [4.7K]

Answer:

1/4 or 0.25

Step-by-step explanation:

3.2(4m + 10) – (-7.2m) = 37
12.8m+32+7.2m=37
20m= 37-32
20m=5
m=5/20= 1/4 or 0.25

7 0

4 years ago

Yesterday, 58 of the 72 students in a contest gave their speeches. How many students gave their speeches? Write your answer in s

DedPeter [7]

So 58 out of 72
therefor
58/72
divide both by 2
58/2=29
72/2=36

29/36
29 is prime so that is simplest form
29/36 is answer

4 0

3 years ago

Read 2 more answers

(Step to step work)<br><br> sin x(cotx + tanx)

11Alexandr11 [23.1K]

solving $sin(x)(cot(x) + tan(x))$ we get $sec(x)$

Step-by-step explanation:

We need to solve: $sin(x)(cot(x) + tan(x))$

Solving:

We know:

$cot(x)=\frac{cos(x)}{sin(x)}\\ and\,\,tan(x)=\frac{sin(x)}{cos(x)}$

Putting the values of cot(x) and tan(x):

$sin(x)(cot(x) + tan(x))\\=sin(x)(\frac{cos(x)}{sin(x)}+\frac{sin(x)}{cos(x)})$

Taking LCM:

$=sin(x)(\frac{cos(x)cos(x)+sin(x)sin(x)}{sin(x)cos(x)})\\=sin(x)(\frac{cos^2(x)+sin^2(x)}{sin(x)cos(x)})$

We know that: cos^2x+sin^2x=1

and using identity: cos(x)sin(x)=sin(2x)*1/2

$=sin(x)(\frac{1}{sin(2x)\frac{1}{2}})\\=sin(x)(\frac{2}{sin(2x)})$

Using identity: sin(2x)=2cos(x)sin(x)

$=sin(x)(\frac{2}{2sin(x)cos(x)})\\Cancelling\,\,same\,\,terms\,\,in\,\,numerator\,\,and\,\,denominator:\\=\frac{1}{cos(x)} \\=sec(x)$

So, solving $sin(x)(cot(x) + tan(x))$ we get $sec(x)$

Keywords: Trigonometry

Learn more about Trigonometry at:

#learnwithBrainly

8 0

3 years ago