Answer:
As Given △QRS is rotated about point P to △Q′R′S′ .
As we know after rotation by any angle of pre-image neither the shape nor size of the image changes, the image after rotation is congruent to pre image.
Out of the options given
→The corresponding lengths, from the point of rotation, between the pre-image and the image are preserved.
→The corresponding angle measurements in each triangle between the pre-image and the image are preserved.
are true.
The answer you seek you just need to take 325 and divide it by 500 to get .65 and change .65 to 65%. And to make sure you multiply 500 by .65 to get 325.
Hope I helped
The correct answer is:
[B]: "
" .
__________________________________________________________Consider choice [A]: 
;
=
;
= 2 ; "2 ≠ -2" ; so we can rule out: "Choice [A]" .
__________________________________________________________Consider choice [B]: ;
=
;
= "-2" ; Yes!
→ Let us proceed with the final answer choice ;
__________________________________________________________Consider choice [C]:
;
=
;
= 2 ; "2 ≠ -2" ; so we can rule out: "Choice [C]" .
__________________________________________________________The correct answer is:
[B]: "
" .
__________________________________________________________
Answer:
You can not solve it because Side P does not exist
Step-by-step explanation:
<span>If you have an equilateral triangle, the median is also the altitude so - That means that if you draw altitude, it will bisect the base of the triangle and meet at two right angles. That gives you two of the measurements for the right triangle - the side (6) hypotenuse, and the base (3). You can then figure out the height using the Pythagorean as you have the a and the c for the theorem. Then you can use 1/2 base times height to find the area.
</span>
