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Gwar [14]
3 years ago
8

How much does a glass cube with a side of 5-cm weigh if 1cm3 of glass weighs 2 2/5 grams?

Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0

Answer:

300

Step-by-step explanation:

:)

PtichkaEL [24]3 years ago
3 0

The weight of galss cube with side 5 cm is 300 grams

<em><u>Solution:</u></em>

A glass cube is of side length 5 cm

Let us first find the volume of glass cube

<em><u>The volume of cube is given as:</u></em>

volume = (side)^3\\\\volume =5^3 = 125

Thus volume of cube is 125 cm^3

Given that,

1 cm^3 = 2\frac{2}{5} \text{ grams }\\\\1 cm^3 =\frac{12}{5} \text{ grams}

So, weight of 125 cubic centimeter of glass cube is found by multiplying weight of 1 cubic centimeter of glass cube by 125

\text{ Weight of 125 } cm^3 \text{ cube } = \text{ Weight of 1 } cm^3 \text{ cube } \times 125

\text{ Weight of 125 } cm^3 \text{ cube } = \frac{12}{5} \times 125 = 25 \times 12 = 300

Thus weight of galss cube with side 5 cm is 300 grams

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Given: mAngleEDF = 120°; mAngleADB = (3x)°; mAngleBDC = (2x)° Prove: x = 24 3 lines are shown. A line with points E, D, C inters
N76 [4]

Answer:

" Vertical angles are congruent " ⇒ 2nd answer

Step-by-step explanation:

* <em>Look to the attached figure </em>

- There are three lines intersected at point D

- We need to find the missing in step 3

∵ Line FA intersects line EC at point D

- The angles formed when two lines cross each other are called

 vertical angles

- Vertical angles are congruent (vertical angles theorem)

∴ ∠ADC and ∠FDE are vertical angles

∵ Vertical angles are congruent

∴ ∠EDF ≅ ∠ADC

∴ m∠EDF ≅ m∠ADC

∵ m∠EDF = 120° ⇒ given

∵ m∠ADC = m∠ADB + m∠BDC

∴ m∠ADB + m∠BDC = 120°

∵ m∠ADB = (3x)° ⇒ given

∵ m∠BDC = (2x)° ⇒ given

∴ 3x + 2x = 120 ⇒ add like terms

∴ 5x = 120 ⇒ divide both sides by 5

∴ x = 24

Column (1)                                                     Column (2)

m∠EDF = 120°                                               given

m∠ADB = 3 x                                                 given

m∠BDC = 2 x                                                 given

∠EDF and ∠ADC are vertical angles           defin. of vert. ∠s

∠EDF is congruent to ∠ADC                        vertical angles are      

                                                                        congruent  

m∠ADC = m∠ADB + m∠BDC                        angle add. post.

m∠EDF = m∠ADC                                          defin. of cong.

m∠EDF = m∠ADB + m∠BDC                         substitution

120° = 3 x + 2 x                                               substitution

120 = 5 x                                                         addition

x = 24                                                              division  

∴ The missing reason is " vertical angles are congruent "

- From the explanation above ∠ADC and ∠FDE are vertical

 angles then they are congruent according to vertical angle

 theorem

6 0
3 years ago
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Rewrite the function by completing the square<br><br> h(x)=4x^2+4x+1
lisov135 [29]

Answer:

h(x) = 4(x+\frac{1}{2})^{2}

Step-by-step explanation:

h(x)=4x^2+4x+1\\h(x)=4(x^2+x+\frac{1}{4}) \\h(x)=4(x^2+x+\frac{1}{4})\\h(x) = 4(x+\frac{1}{2})^{2}

8 0
2 years ago
Can you please help me understand this question please?
GREYUIT [131]

Answer:

B

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5 0
2 years ago
7. It is impossible for the Census Bureau to obtain all the census data about the
quester [9]

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Calculate the straight line distance between the points (-10, -7) and (-8,1).<br> G.2(B)
tia_tia [17]

Answer:

2√(17) or about 8.2462 units.

Step-by-step explanation:

We want to determine the distance between the two points (-10, -7) and (-8, 1).

We can use the distance formula. Recall that:

\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substitute and evaluate:

\displaystyle \begin{aligned} d &= \sqrt{((-10)-(-8))^2 + ((-7) - (1))^2} \\ \\ &=\sqrt{(-2)^2+(-8)^2} \\ \\ &= \sqrt{(4) + (64)} \\ \\ &= \sqrt{68}\\ \\ &= 2\sqrt{17}\end{aligned}

Hence, the distance between (-10, -7) and (-8, 1) is 2√(17) units or about 8.2462 units.

4 0
2 years ago
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