Answer: Pacific Northwest Animals & Birds
- Spotted and snowy owls.
- Bald and Golden eagles.
- Pileated woodpecker.
- Rufous hummingbird.
- Great Blue Heron and Canada goose.
- Seabirds, including cormorant.
- Bear.
- Olympic marmot.
Kitsap Peninsula:
Marine mammals of the sound include orcas, sea lions, sea otters, gray whales, humpback whales, and harbor seals. Underwater plants provide food, breeding areas, nurseries, and resting places for wildlife in the sound.
The changing quantities in an experiment are called variables. A variable refers to any trait, factor, or a condition, which can prevail in distinct amounts or kinds. An experiment generally exhibits three kinds of variables: independent, dependent, and controlled.
The independent variable refers to the one, which is modified. On the other hand, the dependent variable is implied to observe that how it reacts with the change made to the independent variable. The controlled variables refer to the quantities, which one wants to remain constant.
In the given case, that is, heating a cup of water to witness that whether the sugar will get more easily dissolve. In this, the independent variable refers to the temperature of the water determined in degrees Centigrade. The dependent variable refers to the amount of sugar, which dissolves completely measured in grams.
In this, the controlled variables are stirring and type of sugar. As more stirring might elevate the amount of sugar that dissolves, and different kind of sugars might dissolve in distinct concentrations. So, in order to make sure a fair test, there is a need to keep these variables similar for each cup of water.
Limestone.
It is a sedimentary rock composed of calcite and aragonite. It is used as a building material mainly because it is easily available and easy to work with.
Limestone is used in the manufacture of steel as it is the primary raw material that helps to remove impurities from the iron ore and produces waste matter that has low melting point and viscosity
Answer:
Half would have the genotype Aa.
Explanation:
Given that the genotype of both of the parents was "Aa"; both parents would make two types of gametes. The 50% gametes from each parent would carry allele "A" while the rest 50% gametes from each parent would carry allele "a".
The random fusion of gametes of two parents would give the progeny with genotype ratio 1/4 AA: 1/2 Aa: 1/4 aa.
