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bija089 [108]
3 years ago
12

To make the swim team Pedro must swim 400 m in less than seven minutes Pedro where the first 200 minutes in 2.86 minute he swam

the second 200 meters in 3.95 minutes what is the total amount of time he took to swim 400 m did Pedro make the team
Mathematics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

No he didnt make the team

Step-by-step explanation:

2.86 + 3.95= 6.81

so he swam 400 meters in 6min and 81 sec but theirs 60 sec in every min so realy he swam it in 7 min and 21 sec

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0-11/5-17=11/12 is the answer to your question. The work is the equation.
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A survey of a group of seventh graders and a group of teachers at a local middle school asked how many siblings they each have.
Harlamova29_29 [7]

Answer:

The teachers have more combined siblings than the students.

Select 3 what?

Step-by-step explanation:

3 0
2 years ago
Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
Marat540 [252]

Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

distance from 10-foot pole = x ft

Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

3 0
3 years ago
If you add​ Natalie's age and​ Fred's age, the result is 39. If you add​ Fred's age to 4 times​ Natalie's age, the result is 78.
Darina [25.2K]

Step-by-step explanation:

We can write this word problem as two variables. Let us assume that:

x = Natalie's age

y = Fred's age

The first part of the word problem is that "If you add​ Natalie's age and​ Fred's age, the result is 39." Therefore:

Natalie's age + Fred's age = 39

x + y = 39

This will be our first equation. The second equation can be derived from the statement that "If you add​ Fred's age to 4 times​ Natalie's age, the result is 78." Therefore:

(4 times Natalie's age) + Fred's age = 78

4x + y = 78

We can now form a system of equations and solve for both x and y:

\left \{ {{x + y = 39} \atop {4x + y = 78}} \right.

The simplest way to solve would be using the Substitution method, as seen here:

x + y = 39

y = 39 - x

4x + y = 78

4x + (39 - x) = 78

3x + 39 = 78

3x = 39

x = 13

x + y = 39

13 + y = 39

y = 26

Remember that x = Natalie's age and y = Fred's age. Therefore, Natalie's age is 13 years old and Fred's age is 26 years old.

8 0
2 years ago
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