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alekssr [168]
4 years ago
8

Simplify the equation -2xyz(xy + 3yz)

Mathematics
2 answers:
natka813 [3]4 years ago
8 0
-2x²y²z-6xy²z² is the correct answer yes becuase all you have to do is combine like terms
Sergio [31]4 years ago
4 0
The answer is -2x²y²z-6xy²z²
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A local restaurant is offering a special deal in which customers can receive one appetizer, one entree, and one dessert for a fi
Dmitriy789 [7]
There are105 different choices.
For 1 appetizer, there are 15 different combinations of entrees and desserts. 1 dessert has 5 entrees you can mix, and since there are 3 desserts, there are 15 choices. It goes the same for every appetizer until there is 7x15. 7Ax15choices equals 105 options.
The customer has 105 meal choices.
5 0
3 years ago
A crate contains cylindrical cans of soup for shipment. Each crate is a cube with side lengths of 12in. Each soup can is 5in tal
denpristay [2]
The volume of the cube is base times width times height, or any of these measurements cubed, since they're all the same. 
Therefore, the volume of the cube is:
 12³ = 1728 in³
The volume of the cylinder is π*r²*h, where r is the radius and h is height
Remember that the diameter is twice the radius, so the radius is 2 in and the height is 5 in. 
Therefore, each can has a volume of π * 2² * 5 = 20π
Approximating π as 3.14....
The volume of each can is 62.8 in³
1728 ÷ 62.8 = 27.5
Rounding down, 27 cans can fit in the crate.
This is how I suspect the teach wanted you to solve, since it involves finding the volume of both shapes and using pi. However, this is not actually how many cans can fit, because it does not take into account the fact that not every inch of available space will be used. 

Here is another way to solve,taking this fact into account, that gives the more accurate answer:

Each can has a diameter of 4in, which means that they each require a square of 4 x 4 in to accommodate their base.
The base of each can requires 16 in² of space in the crate. 
The base of the cube is 12 x 12, so the area of the base is 144 in²
144 ÷ 16 = 9, so the base of the cube, or bottom of the box, can fit 9 cans, arranged 3 by 3. 

The cube has a height of 12 inches, and each can is 5 inches tall. Therefore, two of these stacks can fit in the box, for 9 x 2 = 18 cans. 
This is a much better answer, as it takes into account the fact that the cans can't occupy every inch of available space in the cube. 
5 0
4 years ago
BRAINLIEST ANSWER 64 is 80% of what
notka56 [123]

Answer:125%

Step-by-step explanation:

80*100/64=125

5 0
3 years ago
I NEED this answered right NOW please!!!!​
kykrilka [37]
Don’t click the link-
7 0
3 years ago
Read 2 more answers
Please!!! I’ll mark Brainliest!! I really need help!!!
Tatiana [17]

Answer:

(x, \:  \: y) = (4, \:  \:  -  \frac{1}{4} )

Step-by-step explanation:

\frac{1}{4} x + \cancel{ 1 \frac{1}{2} y} =  \frac{5}{8}...(1)  \\  \\  \frac{3}{4} x  - \cancel{ 1 \frac{1}{2} y} = 3 \frac{3}{8} ...(2) \\  -  -  -  -  -  -  -  -  - \\(adding\: equations\: 1 \:\&\:2) \\ ( \frac{1}{4}  +  \frac{3}{4} )x =  \frac{5}{8}  + 3 \frac{3}{8}  \\  \\  \frac{4}{4} x =  \frac{5}{8}  +  \frac{27}{8} \\  \\   x =  \frac{32}{8} \\  \\ x = 4 \\  \\ plug \: x = 4 \: in \: equation \: (1) \\  \\  \frac{1}{\cancel 4}  \times \cancel 4 + 1 \frac{1}{2} y =  \frac{5}{8}  \\  \\ 1 +  \frac{3}{2} y =  \frac{5}{8}  \\  \\ \frac{3}{2} y =  \frac{5}{8}   - 1\\  \\ \frac{3}{2} y =  \frac{5 - 8}{8}\\  \\ \frac{3}{2} y =  \frac{ - 3}{8}\\  \\ y =   \frac{ - 3}{8} \times  \frac{2}{3}  \\  \\ y =  \frac{1}{4}  \\  \\ (x, \:  \: y) = (4, \:  \:  -  \frac{1}{4} )

5 0
3 years ago
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