I NEED this answered right NOW please!!!!

From the topic:areas and volumes

Serggg [28]

this question is unambiguous.

6 0

1 year ago

Either Roman has a date with Malou, or Jeff is sleeping or Hadji is eating.

hjlf

Given that one Friday night, Roman and Malou are busy studying for their Logic exam. Meanwhile, Hadji just tweeted a picture of himself eating crispy pata and sisig. Jeff is sound asleep in his dorm room.

Part A:

The truth value of "Either Roman has a date with Malou, or Jeff is sleeping or Hadji is eating." is obtained as follows:

From the scenario, the truth value of the individual statements are as follows:

Roman has a date with Malou is True

Jeff is sleeping is True

Hadji is eating is True

Thus, the truth value of "True" or "True" or "True" is True.

Therefore, the truth value of "Either Roman has a date with Malou, or Jeff is sleeping or Hadji is eating." is True.

Part B:

The truth value of "Either Jeff is sleeping or Hadji is not eating" is obtained as follows:

From the scenario, the truth value of the individual statements are as follows:

Jeff is sleeping is True

Hadji is not eating is False

Thus, the truth value of "True" or "False" is True.

Therefore, the truth value of "Either Jeff is sleeping or Hadji is not eating" is True.

Part C:

The truth value of "Roman and Malou are on a date and Jeff is sleeping, or Hadji is not eating." is obtained as follows:

From the scenario, the truth value of the individual statements are as follows:

Roman and Malou are on a date is True

Jeff is sleeping is True

Hadji is not eating is False

The truth value of "True" and "True" is True.
The truth value of "True" or "False" is True.

Thus, the truth value of ("True" and "True") or "False" is True.

Therefore, the truth value of "Roman and Malou are on a date and Jeff is sleeping, or Hadji is not eating." is True.

6 0

3 years ago

Read 2 more answers

Pls help due in 10 minutes!!!

Luden [163]

Answer:

$\sf 500,000,000,000=5 \times 10^{11}$

$\sf 0.00000000005=5 \times 10^{-11}$

Step-by-step explanation:

Scientific notation

$\large\boxed{a \times 10^n}$

where:

$1\leq a < 10$

$n$ is any positive or negative whole number.

To convert a number into scientific notation, move the decimal point to the left or right until there is one digit to the left of the decimal point.

The number of times you have moved the decimal point is $n$ .

If the decimal point has moved to the left, $n$ is positive.
If the decimal point has moved to the right, $n$ is negative.

To convert 500,000,000,000 into scientific notation, move the decimal point 11 places to left, so a = 5. As we have moved the decimal point 11 places to the left, the exponent "n" is 11 and is positive.

$\implies \sf 500,000,000,000=5 \times 10^{11}$

To convert 0.00000000005 into scientific notation, move the decimal point 11 places to the right, so a = 5. As we have moved the decimal point 11 places to the right , the exponent "n" is 11 and is negative.

$\implies \sf 0.00000000005=5 \times 10^{-11}$

Learn more about scientific notation here:

brainly.com/question/28235385

8 0

1 year ago

Read 2 more answers

The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab

kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable X can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable X thus follows a Poisson distribution with parameter, λ = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.

The mean of the approximated distribution of X is:

μ = λ = 250

The standard deviation of the approximated distribution of X is:

σ = √λ = √250 = 15.8114

Thus, $X\sim N(250, 250)$

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

$P(235$

$=P(-0.95$

Thus, the value of P (235 < X < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

$P(48$

$=P(-0.28$

Thus, the value of $P(48$ .

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

$P(48$

$=P(-0.40$

Thus, the value of $P(48$ .

(d)

Let the sample size be n.

$P(48$

$0.95=P(-z$

The value of z for this probability is,

z = 1.96

Compute the value of n as follows:

$z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241$

Thus, the sample selected must be of size 240.

5 0

3 years ago

Write a fraction less than 1 with a denominator of 6 that is greater than 3/4

Marizza181 [45]

$\frac{5}{6}$ is a fraction with the denominator 6. It is less than one (5/6 = 0.83 [rounded]. 0.83 is less than 1) but greater than $\frac{3}{4}$ (3/4 = 0.75. 0.75 is less than 0.83)

Note: To turn a fraction into a decimal you simply divide the numerator by denominator. ( $\frac{numerator}{denominator}$ → numerator/denominator → (decimal)

8 0

3 years ago

I NEED this answered right NOW please!!!!​

I NEED this answered right NOW please!!!!