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Masja [62]
2 years ago
7

Which statement best describes the relation (3, 4), (4, 3), (6, 3), (7, 8), (5, 4)?

Mathematics
1 answer:
snow_lady [41]2 years ago
3 0

Answer:

This relation represent y as a function of x, because each value of x is associated with a single value of y

Step-by-step explanation:

we know that

A function is a relation from a set of inputs (x values) to a set of possible outputs (y values) where each input is related to exactly one output

we have the relation

(3, 4), (4, 3), (6, 3), (7, 8), (5, 4)

This relation represent y as a function of x, because each value of x is associated with a single value of y

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a farmer grows corn and soybeans on her 300-acre farm. She wants to plant 110 more acres of soybeans than corn. How many acres o
tigry1 [53]
A) C + S = 300
B) S -C = 110
Adding A and B we get:
2 S = 410
Soybeans = 205 acres
Corn = 95 acres


3 0
3 years ago
In a candy store, a $20.00 jar of candy is labeled,35% off.What is the discount? What is the sales price?
DochEvi [55]

Answer:

13

Step-by-step explanation:

35% = .35

20 • .35 = 7

20 - 7 = 13

3 0
3 years ago
Read 2 more answers
i need help with my math :( im horrable with it i cant do divideing fractions nor multiply and i dont know most of my multiples
vladimir1956 [14]

Step-by-step explanation:

To multiply the fractions, like

\frac{1}{4}  \times  \frac{1}{9}

Multiply the top,

then multiply the bottom.

\frac{1}{4}  \times  \frac{1}{9}  =  \frac{1 \times 1}{4 \times 9}  =  \frac{1}{36}

Try to use a calculator if you aren't arithmetic heavy, but I suggest you to try to remember them because they are going to be helpful for courses like Algebra, Calculus, Statistics, etc.

To divide fractions, like

\frac{ \frac{1}{5} }{ \frac{1}{8} }

You take the top number,

\frac{1}{5}

Then you flip the bottom number,

\frac{8}{1}

Then multiply the two

\frac{1}{5}  \times  \frac{8}{1}  =  \frac{8}{5}

And that is your answer. Comment if you need more clarification

6 0
1 year ago
Solve the following system by any method -8x-8y=0 -8x+2y=-20
iVinArrow [24]
                     \fbox{Solution by using Matrix} 

\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20

\text{Rewrite the linear equations above as a matrix} 

\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right] 

\text{Apply to Row2 : Row2 + Row1} 

\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right] 

\text{ Simplify rows} 

\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right] 

\text{Note: The matrix is now in echelon form.}\text{The steps below are for back substitution.} 

\text{Apply to Row1 : Row1 + 8 Row2} 

\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right] 

\text{ Simplify rows}  

\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right] 

\text{Therefore, the solution is} 

x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}
7 0
2 years ago
NEED HELP ON MATH ASAP
RSB [31]
I think it’s A but I’m not sure
7 0
3 years ago
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