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Elis [28]
3 years ago
13

Assume a bank loan requires an interest payment of $85 per year and a principal payment of $1,000 at the end of the loan's eight

-year life. What would be the present value of this loan if it carried a 10% interest rate?
Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0

Answer:

The present value is  PV  = \$ 396,987

Step-by-step explanation:

From the question we are told that

   The  interest payment per year is  C =  \$ 85

    The principal payment is  P =  \$ 1000

     The  duration is  n =  8   years

      The  interest rate is  r =  10\%  =  0.10

The present value is  mathematically represented as

      PV  =  [ \frac{C}{r} *  [1 - \frac{1 }{ (1 +r)^n} ] + \frac{P}{(1 + r)^n}  ]

substituting values

      PV  =  [ \frac{85}{0.10} *  [1 - \frac{1 }{ (1 +0.10)^8} ] + \frac{1000}{(1 + 0.10)^ 8}  ]

      PV  = \$ 396,987

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How many seconds will it take for the penny to hit the ground?
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1 second

Step-by-step explanation:

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3 years ago
Line MN passes through points M4, 3) and M7, 12). If the equation of the line is written in slope-intercept form, y-mx+ b, what
Butoxors [25]

Answer:

<h2>b = -9</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points M(4, 3) and N(7, 12). Substitute:

m=\dfrac{12-3}{7-4}=\dfrac{9}{3}=3

Therefore we have the equation:

y=3x+b

Put the coordinates of the point M to the equation:

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4 0
3 years ago
I need some help with this, can someone help me?
Lina20 [59]

Answer:

D. Paul can type 3/4 as fast as Jennifer

Step-by-step explanation:

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3 0
3 years ago
Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




6 0
3 years ago
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