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3 years ago

Answer me if you need a friend Also 5x+25=35 x=

Mathematics

1 answer:

STALIN [3.7K]3 years ago

5 0

Answer:

x = 2

Step-by-step explanation:

You are solving for the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operation, and =

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction.

First, subtract 25 from both sides of the equation:

5x + 25 (-25) = 35 (-25)

5x = 35 - 25

5x = 10

Isolate the variable, x. Divide 5 from both sides:

(5x)/5 = (10)/5

x = 10/5

x = 2

x = 2 is your answer.

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I don’t remember how I get the answer to this. I have the answer key though. Please help, I have a test in an hour

mrs_skeptik [129]

Answer:

f(x) = (x -2)(x -1+3i)(x -1-3i)

Step-by-step explanation:

You can use synthetic division to find the remaining quadratic factor in the cubic. Then any of the usual means of solving the quadratic will help you find its linear factors.

In the attached, I show the synthetic division, the factoring to real numbers, and the solution that finds the complex linear factors by completing the square.

Of course, you know that for zeros a, b, and c, the linear factors are ...

f(x) = (x -a)(x -b)(x -c)

Here, we have a=2, b=1-3i, c=1+3i.

f(x) = (x -2)(x -1+3i)(x -1-3i)

5 0

3 years ago

Read 2 more answers

Determine if the equation below is a function with independent variable x. If so, find the domain. If not, find a value of x to

Andre45 [30]

Answer:

No because it contains points (3,4) and (3,-4). You cannot have a x assigned to more than one y-value if you want it to be a function.

Step-by-step explanation:

A function has one output per input.

If we are trying to determine if the given is a function of x, then x is the input.

However I can get two outputs from plugging in x=3.

$3^2+y^2=25$

$9+y^2=25$

Subtract 9 on both sides:

$y^2=25-9$

$y^2=16$

Take the square root of both sides:

$y=\pm \sqrt{16}$

$y=\pm 4$ .

So input x=3 yields y=4 and y=-4.

Since this input has more than one output then the given is not a function of x.

----Also!

If you graph the equation, it is a circle with radius 5 and center (0,0). So I could I plug in any number for x between -5 and 5 excluding -5 and 5 which would yield only one output each. Since plugging in either one gives:

$(\pm 5)^2+y^2=25$