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shusha [124]
2 years ago
14

Some softball players hit a softball. Amalia hit the softball 36 inches. Nick hit the softball 6 feet. Lila hit the softball 108

inches. Pablo hit the softball 2 yards. Which two players hit the softball the same distance?
Mathematics
2 answers:
juin [17]2 years ago
8 0

Answer:

6 feet 2 yards

Step-by-step explanation:

Iteru [2.4K]2 years ago
7 0

Answer: Nick and Pablo

Step-by-step explanation:

6 feet and 2 yards are the same distance because each yard is 3 feet

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Suppose given △ABD and △CBD.
patriot [66]

Answer:

The required result is proved with the help of angle bisector theorem.

Step-by-step explanation:

Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that \frac{AD}{AB}=\frac{DC}{CB}

Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.

In ΔADB, AE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.

\frac{DE}{EB}=\frac{AD}{AB}   →  (1)

In ΔDCB, CE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment CD to the line segment CB.

\frac{DE}{EB}=\frac{CD}{CB}    →  (2)

From equation (1) and (2), we get

\frac{AD}{AB}=\frac{CD}{CB}

Hence Proved.

5 0
3 years ago
Solve.
Nat2105 [25]

The solution to the algebraic equation, −0.4x − 3.1 = 5.9, is:<u> x = -22.5</u>

Given the algebraic equation, −0.4x−3.1 = 5.9, to solve for x, follow the steps below:

−0.4x − 3.1 = 5.9

  • Add 3.1 to both sides

−0.4x − 3.1 + 3.1 = 5.9 + 3.1

-0.4x = 9

  • Divide both sides by -0.4

-0.4x/-0.4 = 9/-0.4

x = -22.5

Therefore, the solution to the algebraic equation, −0.4x − 3.1 = 5.9, is:<u> x = -22.5</u>

<u></u>

<u></u>

Learn more here:

brainly.com/question/16864747

7 0
2 years ago
The numerator and the denominator of a fraction are thirteen and fifty, respectively. When a certain number is added to this num
Talja [164]
(13 + x)/(50 - x ) = (2/1)
Cross Multiply
2(50-x) = 1(13 + x)
100 - 2x = 13 + x
add 2x to both sides
100 -2x + 2x = 13 + x + 2x
100 = 13 + 3x
Subtract 13 from both sides
100 - 13 = 13 - 13 + 3x
87 = 3x
divide both sides by 3
29 = x

(13 + 29)/(50-29) = 42/21 = 2 to 1 ratio
7 0
2 years ago
Read 2 more answers
Give the answer to the question below.
alexira [117]

Answer:

1/4 assuming x is not 0

Step-by-step explanation:

x^0 is 1 and 1/4 * 1 = 1/4

4 0
3 years ago
Suppose that the amount of time T a customer spends in a bank is exponentially distributed with an average of 10 minutes. What i
Bad White [126]

Answer:

The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

Step-by-step explanation:

The random variable <em>T</em> is defined as the amount of time a customer spends in a bank.

The random variable <em>T</em> is exponentially distributed.

The probability density function of a an exponential random variable is:

f(x)=\lambda e^{-\lambda x};\ x>0

The average time a customer spends in a bank is <em>β</em> = 10 minutes.

Then the parameter of the distribution is:

\lambda=\frac{1}{\beta}=\frac{1}{10}=0.10

An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.

That is, <em>P</em> (<em>X</em> > <em>s</em> + <em>x</em> | <em>X</em> ><em> s</em>) = <em>P</em> (<em>X</em> > <em>x</em>)

So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is:

P (X > 15 | X > 10) = P (X > 5)

\int\limits^{\infty}_{5} {f(x)} \, dx =\int\limits^{\infty}_{5}  {\lambda e^{-\lambda x}} \, dx\\=\int\limits^{\infty}_{5}  {0.10 e^{-0.10 x}} \, dx\\=0.10\int\limits^{\infty}_{5}  {e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10}|^{\infty}_{5}\\=[-e^{-0.10 \times \infty}+e^{-0.10 \times 5}]\\=0.6065

Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

8 0
2 years ago
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