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sashaice [31]
4 years ago
8

Determine the initial valuation of each asset, assuming that immediately after acquisition, Samtech demolished the building. Dem

olition costs were $260,000 and the salvaged materials were sold for $6,500. In addition, Samtech spent $80,000 clearing and grading the land in preparation for the construction of a new building
Mathematics
1 answer:
LiRa [457]4 years ago
6 0

Answer:

purchase cost + 338500

Step-by-step explanation:

given that immediately after acquisition, Samtech demolished the building. Demolition costs were $260,000 and the salvaged materials were sold for $6,500.

In addition, Samtech spent $80,000 clearing and grading the land in preparation for the construction of a new building.

Thus initial valuation of the asset = purchase cost + expenses - sale value of salvaged materials

Hence here we get

initial value = purchase cost + 260000-6500+80000

= purchase cost + 338500

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Step2247 [10]
Sally = 1/3
Jerry = 5/6
David = 1/2
Mona = 1 - 7/8 = 1/8

So, the biggest fraction among them is 5/6.

Jerry has completed the most work time. 
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3 years ago
What is the value of x in the equation 1/5x – 2/3y = 30, when y = 15?
Maksim231197 [3]
X=200
2/3 of 15 is 10 make that negative add it to the other side 1/5x = 40 and then multiply 40 by 5 to get your answer
Check 
1/5 of 200 is 40 - 10 = 30
40-10=30
30=30
6 0
3 years ago
A book store is having a 30% off sale. Diary of a wimpy kid books are now $6.30 each. What was the original price of the books?
inn [45]
6.30x0.3= 1.89

6.30+1.89=8.19
5 0
3 years ago
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
In a population of 10,000 geese the growth rate is 4% per year. What is the total increase in population over 4 years? Round you
omeli [17]

Answer:

Step-by-step explanation:

10000*4%= 400 Geese year1

10400*4%=416 Geese  year 2

10816*4%= 432.64 Geese year 3

11,248.64*4%= 449.95 Geese. year 4

11248.64+449.95= 11698.59

11698.59-10000=1698.59

Increased by 1699 Geese.

3 0
3 years ago
Read 2 more answers
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