If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
Answer:
AM ONLI GR 4 SORI HEHEhehe
Answer:
Step-by-step explanation:
It's like solving any equation, except we have letters instead of numbers .
k = 3tm + rs {subtract rs from both sides}
k - rs = 3tm {divide both sides by (3m)}
{swap sides}
m≠0
{m must be ≠0 because you cannot divide by 0. There is no t for m=0}
Zoe spend $2339.22 because you just need to multiply the given
Formula:
A(t)=P(1+(r/n))^)nt)
A(4)=2500(1+(0.04/4))^(4*4)
A(4) = 2500(1.01)^16
A(4) = 2500*1.1726
<span>A(4) = $2931.45</span>
